Question

我有一个文件，每行包含一组字节，例如：

4655d16c690f2789c2d3e803e388637f
16161b1504137217336d403e2a03c669
fa79c5ffe35d112915f0f3243fc68fb4
87d57d0a63e52b6df869eb5c0aac4328
640c2eefb7829d863f7aa686bc513acc
4024767c463558b7c7cd0ffd4f0aaa6d
18ee0b17f5b5206df0443e658b105990
7b40bf42d2cfc290eed4c4edcb9d3e91
b57dad9833c3e174e05a5ae75cac70ed

我想转换数组中的行，然后转换十进制的字节，例如：

4655d16c690f2789c2d3e803e388637f

结果是：

46 55 d1 6c 69 0f 27 89 c2 d3 e8 03 e3 88 63 7f

然后转换为十进制的每个字节：

 [70,85,209,108,105,15,39,137,194,211,232,3,136,227,99,127]

我尝试使用此代码，

with open(Srcpath, 'r') as f:
        with open(Destpath, 'w') as fp:
            for key in f:
                key_Separated=[key[i:i+2] for i in range(0, len(key), 2)]
                rejoined = ' '.join(key_Separated)
                Decimal= [i for i, b in enumerate(rejoined ) if b=='1']
                print(Decimal)
                fp.write(str(Decimal))

所以它给出了错误的结果：

[43]
[21, 45]
[27, 42]
[13, 31, 37, 42]
[16, 21, 28]
[13, 36]
[12, 43, 46]
[0, 6, 18, 27, 37]

我怎么能纠正他们？

Answer 1

这应该可以解决问题：

import re

data = '''4655d16c690f2789c2d3e803e388637f
16161b1504137217336d403e2a03c669
fa79c5ffe35d112915f0f3243fc68fb4
87d57d0a63e52b6df869eb5c0aac4328
640c2eefb7829d863f7aa686bc513acc
4024767c463558b7c7cd0ffd4f0aaa6d
18ee0b17f5b5206df0443e658b105990
7b40bf42d2cfc290eed4c4edcb9d3e91
b57dad9833c3e174e05a5ae75cac70ed'''

data = [re.findall('..', item) for item in data.split('\n') if item]
result = [[int(x, 16) for x in item] for item in data]

Answer 2

Python有一个内置的库，可以进行所需的转换。鉴于您的数据为data.txt：

#!python3
from binascii import unhexlify
from pprint import pprint

with open('data.txt') as f:
    pprint([list(unhexlify(line.strip())) for line in f])

[[70, 85, 209, 108, 105, 15, 39, 137, 194, 211, 232, 3, 227, 136, 99, 127],
 [22, 22, 27, 21, 4, 19, 114, 23, 51, 109, 64, 62, 42, 3, 198, 105],
 [250, 121, 197, 255, 227, 93, 17, 41, 21, 240, 243, 36, 63, 198, 143, 180],
 [135, 213, 125, 10, 99, 229, 43, 109, 248, 105, 235, 92, 10, 172, 67, 40],
 [100, 12, 46, 239, 183, 130, 157, 134, 63, 122, 166, 134, 188, 81, 58, 204],
 [64, 36, 118, 124, 70, 53, 88, 183, 199, 205, 15, 253, 79, 10, 170, 109],
 [24, 238, 11, 23, 245, 181, 32, 109, 240, 68, 62, 101, 139, 16, 89, 144],
 [123, 64, 191, 66, 210, 207, 194, 144, 238, 212, 196, 237, 203, 157, 62, 145],
 [181, 125, 173, 152, 51, 195, 225, 116, 224, 90, 90, 231, 92, 172, 112, 237]]

如果使用Python 2，字节字符串不会转换为整数列表，那么还有另一个循环来进行转换：

#!python2
from binascii import unhexlify
from pprint import pprint

with open('data.txt') as f:
    pprint([[ord(b) for b in unhexlify(line.strip())] for line in f])

如何将数组中的一组字节从hexa转换为十进制（python）？

2 个答案: