Question

我有一个具有以下结构的商店数据库：

s_articles: all products
id | name | mode

s_order: all orders
id | ordertime | userId | status

s_order_details: all line items for an order
id | orderId | articleId

现在我希望实现以下目标：我想现在有多少用户在过去90天内购买了产品，并且在过去90天之前购买了相同的产品。

我是这样做的：我收到所有文章，然后我会计算在过去90天"boughtBefore90"之前购买过该文章的所有客户，然后我有另一个子选择与另一个子选择我在哪里收集过去90天内购买该产品的所有用户，并在此之前购买该产品并将其保存在"boughtLast90"。

然后我计算保留率。这适用于一种产品，但不适用于整篇文章数据库。有没有办法编写这个具有更好性能的SQL？

我的查询如下：

select articleId, articleName, boughtBefore90, boughtLast90, boughtLast90/boughtBefore90 as 'retention'
FROM 

(select
    s_articles.id as 'articleId',
    s_articles.name as 'articleName',
    (select count(*)
        FROM s_order_details as s_order_details_2
        join s_order as s_order_2 on s_order_2.Id = s_order_details_2.orderId
        where s_order_details_2.articleId = s_articles.id
        and (s_order_2.status = 0 or s_order_2.status = 2)
        and s_order_2.ordertime > '2017-01-01 00:00:00'
        and s_order_2.ordertime <  '2017-03-09 23:59:59'
    ) as 'boughtBefore90',
    (select count(*) from s_order_details as s_order_details_3
        join s_order as s_order_3 on s_order_3.id = s_order_details_3.orderId 
        where s_order_3.ordertime > '2017-03-10 00:00:00'
        and s_order_3.ordertime < '2017-06-07 23:59:59'
        and s_order_details_3.articleId = s_articles.id
        and (s_order_3.status = 0 or s_order_3.status = 2)
        AND s_order_3.userId = (
            select DISTINCT(s_order_4.userId) from s_order_details as s_order_details_4
            join s_order as s_order_4 on s_order_4.id = s_order_details_4.orderId 
            where s_order_4.ordertime > '2017-01-01 00:00:00'
            and s_order_4.ordertime < '2017-03-09 23:59:59'
            and s_order_details_4.articleId = s_articles.id
            and s_order_3.userId = s_order_4.userId
            and (s_order_4.status = 0 or s_order_4.status = 2))
    ) as 'boughtLast90'
    from
    s_articles
    join s_order_details on s_order_details.articleID = s_articles.id
    join s_order on s_order.id = s_order_details.orderId
    WHERE s_articles.mode = 0
    AND s_order_details.modus = 0
    AND (s_order.status = 2 or s_order.status = 0)
    group by s_articles.id) as resulttable;

谢谢！

Answer 1

这似乎是一个非常简单的查询。以下是客户和文章列表：

select o.customerid, od.articleid
from s_orders o join
     s_order_details od
     on od.orderid = o.id
group by o.customerid, od.articleid
having max(o.ordertime) > curdate() - interval 90 days and
       min(o.ordertime) <= curdate() - interval 90 days;

如果您想要计数，请将其用作子查询，并使用count(*)（对于客户/文章对）或count(distinct customerid)（对于客户数量）。

MySQL查询没有回来 - 性能增强？

1 个答案: