Question

- 溶液 -

SELECT Table1.unvan, Table2.sayi FROM 
(SELECT id , unvan FROM unvan WHERE id IN 
(SELECT unvani FROM personel WHERE gorev_yeri IN 
(SELECT id FROM gorev_yeri WHERE il_id="34") ) ) AS Table1 
JOIN
( SELECT unvani as id , count(*) AS sayi FROM personel WHERE gorev_yeri IN (SELECT id FROM gorev_yeri WHERE il_id="34") GROUP BY unvani ) AS Table2 
ON Table1.id = Table2.id

- 编辑 -

当我使用join时出现此错误：＃1064 - 您的SQL语法出错;查看与您的MySQL服务器版本对应的手册，以获得在＆＃39; AS table1

附近使用的正确语法

我有2个查询，我想加入他们。

It is first.

SELECT id
     , unvan 
  FROM unvan 
 WHERE id IN (SELECT unvani 
                FROM personel 
               WHERE gorev_yeri IN (SELECT id 
                                      FROM gorev_yeri 
                                     WHERE il_id="34")
              )

It is second one.

SELECT unvani as id
     , count(*) AS sayi 
 FROM personel 
WHERE gorev_yeri IN (SELECT id 
                       FROM gorev_yeri 
                        WHERE il_id="34") GROUP BY unvani

我需要这个：

unvan |卅一

-------- | ----

Answer 1

（SELECT id ，unvan 来自unvan WHERE id IN（SELECT unvani 来自个人在哪里gorev_yeri IN（SELECT id 来自gorev_yeri WHERE il_id =“34”）））表1

加入

（ SELECT unvani as id，count（*）AS sayi FROM personel WHERE gorev_yeri IN（SELECT id FROM gorev_yeri WHERE il_id =“34”）GROUP BY unvani ）表2

on table1.id = table2.id;

Answer 2

基于提供的错误

应该是这样的：

SELECT `Table1`.unvan, `Table2`.id
FROM
(
    SELECT id
    , unvan 
   FROM unvan 
   WHERE id IN (SELECT unvani 
            FROM personel 
           WHERE gorev_yeri IN (SELECT id 
                                  FROM gorev_yeri 
                                 WHERE il_id="34")
          )
) AS `Table1`

JOIN

(
SELECT unvani as id
 , count(*) AS sayi 
 FROM personel 
 WHERE gorev_yeri IN (SELECT id 
                   FROM gorev_yeri 
                    WHERE il_id="34") GROUP BY unvani
) AS `Table2`

ON `Table1`.id = `Table2`.id

MySql连接多个select子查询

- 编辑 -

当我使用join时出现此错误：＃1064 - 您的SQL语法出错;查看与您的MySQL服务器版本对应的手册，以获得在＆＃39; AS table1

2 个答案: