Question

我想为现有用户编写一个简单的登录脚本，我已经为它创建了一个字典，但我的代码不起作用。

我尝试过以下方法：

d = {'apple':'red','green':'lettuce','yellow':'lemon','orange':'orange'}
print "Please enter your username: "
user_name = raw_input()
print "Please enter your password: "
password = raw_input
for user_name,password in d:
    if user_name in d and password in d:
        print "great"
    else:
        print "Password incorrect!"

代码不起作用，我的密码总是不正确。

Answer 1

d = {'apple':'red','green':'lettuce','yellow':'lemon','orange':'orange'}

user_name = raw_input() #apple
password = raw_input() # red

if user_name in d.keys():
    #check if username: apple == password : red (key=value)
    if password == d.get(user_name) 
        print "great"
    else:
        print "Password incorrect!"

Answer 2

有些事情你做错了：

您未在密码

raw_input()

您以明文
raw_string()可以将字符串作为参数，这样您就可以摆脱print语句
您正在检查用户名/密码是否在d中，但您实际上应该在密钥中查找用户名并在密码中查找值。已经在for循环上方定义了更多user_name和password，这使得for循环完全错误。

因此，一个简单的解决方案是：

d = {'apple': 'red', 'green': 'lettuce', 'yellow': 'lemon', 'orange': 'orange'}

user_name = raw_input("Please enter your username: ")
password = raw_input("Please enter your password: ")

if password == d.get(user_name):
  print True
else:
  print False

Answer 3

您将收到错误：“对于user_name，密码在d：”

Python ValueError: too many values to unpack

正确的代码将是：

d = {'apple':'red','green':'lettuce','yellow':'lemon','orange':'orange'} 
print "Please enter your username: " 
user_name = raw_input() 
print "Please enter your password: " 
password = raw_input() 
for user,passw in d.iteritems(): 
    if user == user_name and password == passw :
         print "great"
         exit(0)
print "Password incorrect!"

我想阅读并确认字典中的数据

3 个答案: