我有一张30列的桌子, 它包含1000行。 我想要一个LINQ查询,它检查所有列中的特定值并将结果转换为列表。
例如:
RewriteCond %{HTTPS} off [OR]
RewriteCond %{HTTP_HOST} ^www\.somedomain\.com$ [NC]
RewriteRule ^/?$ https://somedomain.com [L,R=301]
如何使用一个LINQ查询完成上述操作。非常感谢任何帮助。
答案 0 :(得分:2)
对于您的请求,所有字段都应该具有相同的类型,至少在静态类型的C#中。
方法Queriable.Where
将Expression<Func<T, bool>>
谓词作为参数。因此,您需要将谓词o.p1 == val || o.p2 == val || o.p3 = val ...
构建为Expression
值。此处o
是Expression<Func<T, bool>>
的参数:
public Expression BuildExpression<TObj, TVal>(TObj obj, TVal val)
{
Expression<Func<TObj, bool>> predicate = (o) => o.p1 == val || ... || o.pN == val;
return predicate;
}
但我们需要为TObj
类型为TVal
的所有属性动态构建谓词。
为简化代码,我们将构建相等的表达式false || o.p1 == val || ... || o.pN == val
。
public Expression<Func<TObj, bool>> BuildExpression<TObj, TVal>(TVal val)
{
var parameter = Expression.Parameter(typeof(TObj), "o");
var valExpression = Expression.Constant(val, typeof(TVal));
var body = Expression.Constant(false, typeof(bool));
var properties = typeof(TObj).GetProperties()
.Where(p => p.PropertyType == typeof(TVal));
foreach (var property in properties)
{
var propertyExpression = Expression.Property(parameter, property);
var equalExpression = Expression.Equal(propertyExpression, valExpression);
body = Expression.Or(body, equalExpression);
}
return Expression.Lambda<Func<TObj, bool>>(body, parameter);
}
. . .
using (var dbContext = new DbContext())
{
var whereExpression = BuildExpression<User, string>("foo");
var contaningsFoo = dbContext.Users.Where(whereExpression);
}
答案 1 :(得分:0)
我得到了答案但是不是完美答案但是工作得很好
public class GenericList<T>
{
void Add(T input) { }
public List<T> SerachFun(List<T> input, string search)
{
List<T> output = new System.Collections.Generic.List<T>();
foreach (var aa in input)
{
var columns = aa.GetType().GetProperties().ToList();
foreach (var bb in columns)
{
var cccc = bb.GetValue(aa);
bool result = cccc.ToString().Contains(search);
if (result)
{
output.Add(aa);
continue;
}
}
}
return output;
}
}
创建的通用类对象
public GenericList<table1> g = new GenericList<table1>();
调用的通用类方法:
var tabledetails=db.table1.ToList();
var resultcommonsearch = g.SerachFun(tabledetails, "Dhoni");
答案 2 :(得分:0)
使用代码
public GenericList<table1> g = new GenericList<table1>();
var tabledetails=db.table1.ToList();
var resultcommonsearch = g.SerachFun(tabledetails, "Dhoni");
尝试调用方法
a = [{"ID83": {"Job1": {"Job_Num": "ABC.179", "Job_PNo": "26", "Job_SNo": "750", "Job_name": "Job1"}}},
{"ID84": {"Job1": {"Job_Num": "ABC.180", "Job_PNo": "27", "Job_SNo": "850", "Job_name": "Job1a"}}},
{"ID85": {"Job2": {"Job_Num": "DEF.20", "Job_PNo": "28", "Job_SNo": "950", "Job_name": "Job2"}}},
{"ID86": {"Job3": {"Job_Num": "CDE.150", "Job_PNo": "29", "Job_SNo": "50", "Job_name": "Job3"}}},
{"ID87": {"Job2": {"Job_Num": "XYZ.20", "Job_PNo": "30", "Job_SNo": "200", "Job_name": "Job2a"}}},
{"ID83": {"Job3": {"Job_Num": "CDE.151", "Job_PNo": "30", "Job_SNo": "55", "Job_name": "Job3a"}}},
]
ret = []
for d in a:
line = []
for (k,v) in d.items():
line.append(k)
inner_dict = list(v.values())[0]
line.append(inner_dict['Job_name'])
line.append(inner_dict['Job_Num'])
line.append(inner_dict['Job_PNo'])
line.append(inner_dict['Job_SNo'])
ret.append(line)
csvstr = '\n'.join([','.join(i) for i in ret])
with file('out.csv', 'w') as f:
f.write(csvstr)