Question

我有两个数组secondArray和mac_id我必须将它们组合起来，以便根据$firstArray = [ [ 'id' => 1, 'mac_id' => 2, 'type' => 'car' ], [ 'id' => 2, 'mac_id' => 2, 'type' => 'mobile' ], [ 'id' => 3, 'mac_id' => 1, 'type' => 'tv' ] ] $secondArray = [ [ 'id' => 1, 'mac_id' => 2, 'type' => 'fruit' ], [ 'id' => 2, 'mac_id' => 1, 'type' => 'car' ], [ 'id' => 3, 'mac_id' => 1, 'type' => 'car' ], ]生成o / p

[
    2 => [
        'firstArray' => [
            [
            'id' => 1,
            'mac_id' => 2,
            'type' => 'car'
            ],

            [
            'id' => 2,
            'mac_id' => 2,
            'type' => 'mobile'
            ],
        ],
        'secondArray' => [
            [
            'id' => 1,
            'mac_id' => 2,
            'type' => 'fruit'
            ]
        ]


    ],
    1 => [
        'firstArray' => [
            [
            'id' => 1,
            'mac_id' => 2,
            'type' => 'car'
            ],
            [
            'id' => 2,
            'mac_id' => 1,
            'type' => 'car'
            ]

        ],
        'secondArray' => [
            [
            'id' => 3,
            'mac_id' => 1,
            'type' => 'car'
            ]
        ]
    ]
]

预期o / p

$(".mybox").select2({
 containerCssClass: "pink",
   templateResult: function (data, container) {
    if (data.element) {
      $(container).addClass($(data.element).attr("class"));
    }
    return data.text;
  }
});

Answer 1

从你的o / p希望这是你想要的

$firstArray = [
        [
        'id' => 1,
        'mac_id' => 2,
        'type' => 'car'
        ],

        [
        'id' => 2,
        'mac_id' => 2,
        'type' => 'mobile'
        ],

        [
        'id' => 3,
        'mac_id' => 1,
        'type' => 'tv'
        ]
];

$secondArray = [
        [
        'id' => 1,
        'mac_id' => 2,
        'type' => 'fruit'
        ],
        [
        'id' => 2,
        'mac_id' => 1,
        'type' => 'car'
        ],
        [
        'id' => 3,
        'mac_id' => 1,
        'type' => 'car'
        ],
    ];

if(count($secondArray) > count($firstArray))
    $loop_through= $secondArray;
else
    $loop_through= $firstArray;

$mac_id_array = array();
$new_array = array();
foreach ($loop_through as $key => $value) {
    # code...
    $mac_id =$value['mac_id'] ;

    if(!in_array($mac_id, $mac_id_array))
    {
        $mac_id_array[]=$mac_id;
        $key_1 = array_keys(array_column($firstArray, 'mac_id'),$mac_id);

        $key_2 = array_keys(array_column($secondArray, 'mac_id'),$mac_id); //array_search($mac_id, array_column($secondArray, 'mac_id'));
        if(count($key_1))
        {
            $tmp_array = array();
            foreach ($key_1 as $tmp_key) {
                $tmp_array[] = $firstArray[$tmp_key];
            }

            $new_array[$mac_id]['firstArray'] = $tmp_array;
        }

        if(count($key_2))
        {
            $tmp_array = array();
            foreach ($key_2 as $tmp_key) {
                $tmp_array[] = $secondArray[$tmp_key];
            }
            $new_array[$mac_id]['secondArray'] = $tmp_array;
        }

    }

}
echo "<pre>";
print_r($new_array);?>

检查o / p：

https://eval.in/813310

基于公共密钥在PHP中组合两个数组

1 个答案: