Hibernate - 列名为

Question

我有两张桌子：

• 客户：ID（密钥）
• PERSONAL_DATA：ID（密钥），CUSTOMER_ID

是否可以创建 XML 配置：

• 一对一关系CUSTOMERS.ID - ＆gt; PERSONAL_DATA.CUTOMER.ID
• CUSTOMERS pojo类中PERSONAL_DATA类型的属性？

Answer 1

是的，xmls可能如下所示：

1. CUSTOMERS xml：

<hibernate-mapping>
	<class name="QUALIFIED_NAME_OF_CUSTOMERS" table="CUSTOMERS" catalog="YOUR_DATABASE_NAME">
		<id name="id" type="java.lang.Integer">
			<column name="id" />
			<generator class="identity" />
		</id>
		<one-to-one name="PERSONAL_DATA" class="QUALIFIED_NAME_OF_PERSONAL_DATA"
			cascade="save-update"></one-to-one>
	</class>
</hibernate-mapping>

1. PERSONAL_DATA xml：

<hibernate-mapping>
    <class name="QUALIFIED_NAME_OF_PERSONAL_DATA" table="PERSONAL_DATA"
        		catalog="YOUR_DATABASE_NAME">
        <id name="customer_id" type="java.lang.Integer">
    		    <column name="customer_id" />
            <generator class="foreign">
				        <param name="property">CUSTOMERS</param>
			      </generator>
    		</id>
        <one-to-one name="CUSTOMERS" class="QUALIFIED_NAME_OF_CUSTOMERS"
        			constrained="true">
        </one-to-one>
        <property name="id" type="java.lang.Integer">
            <column name="id" />
        </property>
        		
      </class>
</hibernate-mapping>