我想使用漂亮的汤来找到儿童标签(收益或损失)大于0的标签。然后我想打印内部标签的内容“收益”“损失”和“band.textualrepresentation” ”。这本质上是我想要的脚本(虽然这个不起作用)。
import sys
from BeautifulSoup import BeautifulSoup as Soup
def parseLog(file):
file = sys.argv[1]
handler = open(file).read()
soup = Soup(handler)
for anytype in soup('anytype', 'gains'.string>0 || 'losses'.string>0):
gain = anytype.gains.string
loss = anytype.losses.string
band = anytype.band.textualrepresentation.string
print gain loss band
parseLog(sys.argv[1])
我很早就遇到了麻烦,我甚至无法打印收益内容,更不用说打印符合一定条件的内容了。我目前的剧本
def parseLog(file):
file = sys.argv[1]
handler = open(file).read()
soup = Soup(handler)
for anytype in soup.findall('anytype'):
gain = anytype.fetch('gains')
print gain
parseLog(sys.argv[1])
返回
Traceback (most recent call last):
File "./soup.py", line 13, in <module>
parseLog(sys.argv[1])
File "./soup.py", line 9, in parseLog
for anytype in soup.findall('anytype'):
TypeError: 'NoneType' object is not callable
示例输入
<anytype xsi:type="GainLossStruct">
<band>
<textualrepresentation>
22q11.1
</textualrepresentation>
</band>
<gains>
2
</gains>
<losses>
1
</losses>
<structs>
0
</structs>
</anytype>
<anytype xsi:type="GainLossStruct">
<band>
<textualrepresentation>
22q11.2
</textualrepresentation>
</band>
<gains>
0
</gains>
<losses>
1
</losses>
<structs>
0
</structs>
</anytype>
<anytype xsi:type="GainLossStruct">
<band>
<textualrepresentation>
22q12
</textualrepresentation>
</band>
<gains>
0
</gains>
<losses>
0
</losses>
<structs>
0
</structs>
</anytype>
示例输出
2 1 22q11.1
0 1 22q11.2
更新 目前的解决方案
import sys
from BeautifulSoup import BeautifulSoup as Soup
def parseLog(file):
file = sys.argv[1]
handler = open(file).read()
soup = Soup(handler)
for anytype in soup(lambda x: x.name=='anytype' and (hasattr(x, 'gains') and int(x.gains.string) > 0 or hasattr(x, 'losses') and int(x.losses.string) > 0)):
gain = anytype.gains.string
loss = anytype.losses.string
band = anytype.band.textualrepresentation.string
print gain, loss, band
parseLog(sys.argv[1])
仍然返回错误
Traceback (most recent call last):
File "./soup.py", line 15, in <module>
parseLog(sys.argv[1])
File "./soup.py", line 9, in parseLog
for anytype in soup(lambda x: x.name=='anytype' and (hasattr(x, 'gains') and int(x.gains.string) > 0 or hasattr(x, 'losses') and int(x.losses.string) > 0)):
File "/Users/jacob/homebrew/lib/python2.7/site-packages/BeautifulSoup.py", line 659, in __call__
return apply(self.findAll, args, kwargs)
File "/Users/jacob/homebrew/lib/python2.7/site-packages/BeautifulSoup.py", line 849, in findAll
return self._findAll(name, attrs, text, limit, generator, **kwargs)
File "/Users/jacob/homebrew/lib/python2.7/site-packages/BeautifulSoup.py", line 377, in _findAll
found = strainer.search(i)
File "/Users/jacob/homebrew/lib/python2.7/site-packages/BeautifulSoup.py", line 966, in search
found = self.searchTag(markup)
File "/Users/jacob/homebrew/lib/python2.7/site-packages/BeautifulSoup.py", line 924, in searchTag
or (markup and self._matches(markup, self.name)) \
File "/Users/jacob/homebrew/lib/python2.7/site-packages/BeautifulSoup.py", line 983, in _matches
result = matchAgainst(markup)
File "./soup.py", line 9, in <lambda>
for anytype in soup(lambda x: x.name=='anytype' and (hasattr(x, 'gains') and int(x.gains.string) > 0 or hasattr(x, 'losses') and int(x.losses.string) > 0)):
AttributeError: 'NoneType' object has no attribute 'string'
即使我将for循环减少到
for anytype in soup(lambda x: x.name=='anytype' and (hasattr(x, 'gains'))):
gain = anytype.gains.string
print gain
我还是
Traceback (most recent call last):
File "./soup.py", line 13, in <module>
parseLog(sys.argv[1])
File "./soup.py", line 10, in parseLog
gain = anytype.gains.string
AttributeError: 'NoneType' object has no attribute 'string'
答案 0 :(得分:2)
我会将整个文档解析成一个pandas数据帧,然后执行任何操作;这可能会使数据清理过程更加透明和易于理解。
我将在这里使用xmltojson
,因为我不熟悉美丽的汤(尽管我必须将整个内容包含在“document”标签中,因为要使其成为有效的XML):
import xmltojson
import pandas as pd
with open(file) as f:
j = eval(xmltojson.parse("<document> "+ f.read() + "</document>"))
df = pd.io.json.json_normalize(j['document']['anytype'])
df.columns = ['type', 'band', 'gain', 'loss', 'struct']
df[(df.gain > '0') | (df.loss > '0')][['band', 'gain', 'loss']]
band gain loss
0 22q11.1 2 1
1 22q11.2 0 1
答案 1 :(得分:1)
代码应为:
for anytype in soup(lambda x: x.name=='anytype' and (int(x.gains.string) > 0 or int(x.losses.string) > 0)):
gain = anytype.gains.string
loss = anytype.losses.string
band = anytype.band.textualrepresentation.string
print gain loss band
python ||
是or
,我们需要在执行整数比较之前将字符串转换为数字,例如int(x.gains.string)
。希望这有帮助。