Question

我试图创建一个来自列表的字符串变量列表只是字母表（不要问为什么，它只是为了程序）

passwords = ["A","B","C","D","E","F","G","H","I","J","K","L","M","N","O","P","Q","R","S","T","U","V","W","X","Y","Z"]

基本上，我曾经有一个变量，它从中获取了4个随机字母，以创建一个看起来像这样的字符串：

correctPassword = random.sample(passwords,4)

我需要的是列表中的4个特定字符来创建相同类型的字符串变量，单词＆＃34; STOP＆＃34;。

我将非常感谢您的回答，我试图从Fallout重新创建黑客迷你游戏，如果有人知道那是什么，谢谢！

Answer 1

我不确定我明白你要做什么，但...... 要创建一个等于“STOP”的字符串变量：

x = "STOP"

代码行

correctPassword = random.sample(passwords,4)

不会创建字符串变量，而是创建4个项目的字符串列表，每个项目都是1个字符的字符串。使用上面定义的x，表达式x == correctPassword将始终为false。

将这些合并为一个字符串：

correctPasswordAsString = ''.join(correctPassword)

如果correctPasswordAsString为“STOP”，则比较x == correctPasswordAsString为true，否则为false。

Answer 2

您可以使用它来创建列表中的字符串变量：

import random
passwords = ["A","B","C","D","E","F","G","H","I","J","K","L","M","N","O","P","Q","R","S","T","U","V","W","X","Y","Z"]
correctPassword = random.sample(passwords,4)
result = ""
result = result.join(correctPassword)
print(result)

并得到类似：STOP

的内容

Python join()方法是一种字符串方法。它将对象列表合并为一个字符串。

Answer 3

您可以按以下方式创建变量：

MATCH (currentBook:BOOK {ISBN: {ISBN}})-[sim:similar*1..3]-(newBook:BOOK {author: {currentAuthor}}) SET newBook.simsUsed = AMOUNT_EXPANDED(sim) RETURN newBook

或者，您可以使用字母的索引：

correctPassword = ["S", "T", "O", "P"]

从字符串中取出某些部分，然后使用它来创建一个字符串变量

3 个答案: