Question

是否可以拥有变量名称空间？我有以下资源：

resources :articles
resources :persons

但我需要将这些范围放在变量名称空间中，以便它响应表单的URL：

':edition/:controller/:action/:id'

例如：

/foobar/article/edit/123或/bazbam/person/edit/345

为每个资源。这可能是resources方法，还是我必须手工制作这些？我不会提前知道:edition的可能值;这些内容会在before_filter中的ApplicationController中查找。

这就是我需要做的全部吗？

scope ':edition' do
  resources :articles
  resources :matches
  resources :teams
end

更新：当使用上面的范围指令时，我得到了我想要的路线：

    articles GET    /:edition/articles(.:format)          {:action=>"index", :controller=>"articles"}
             POST   /:edition/articles(.:format)          {:action=>"create", :controller=>"articles"}
 new_article GET    /:edition/articles/new(.:format)      {:action=>"new", :controller=>"articles"}
edit_article GET    /:edition/articles/:id/edit(.:format) {:action=>"edit", :controller=>"articles"}
     article GET    /:edition/articles/:id(.:format)      {:action=>"show", :controller=>"articles"}
             PUT    /:edition/articles/:id(.:format)      {:action=>"update", :controller=>"articles"}
             DELETE /:edition/articles/:id(.:format)      {:action=>"destroy", :controller=>"articles"}
     matches GET    /:edition/matches(.:format)           {:action=>"index", :controller=>"matches"}
             POST   /:edition/matches(.:format)           {:action=>"create", :controller=>"matches"}
   new_match GET    /:edition/matches/new(.:format)       {:action=>"new", :controller=>"matches"}
  edit_match GET    /:edition/matches/:id/edit(.:format)  {:action=>"edit", :controller=>"matches"}
       match GET    /:edition/matches/:id(.:format)       {:action=>"show", :controller=>"matches"}
             PUT    /:edition/matches/:id(.:format)       {:action=>"update", :controller=>"matches"}
             DELETE /:edition/matches/:id(.:format)       {:action=>"destroy", :controller=>"matches"}
       teams GET    /:edition/teams(.:format)             {:action=>"index", :controller=>"teams"}
             POST   /:edition/teams(.:format)             {:action=>"create", :controller=>"teams"}
    new_team GET    /:edition/teams/new(.:format)         {:action=>"new", :controller=>"teams"}
   edit_team GET    /:edition/teams/:id/edit(.:format)    {:action=>"edit", :controller=>"teams"}
        team GET    /:edition/teams/:id(.:format)         {:action=>"show", :controller=>"teams"}
             PUT    /:edition/teams/:id(.:format)         {:action=>"update", :controller=>"teams"}
             DELETE /:edition/teams/:id(.:format)         {:action=>"destroy", :controller=>"teams"}

我现在可以在我的:edition中引用ApplicationController：

class ApplicationController < ActionController::Base
  protect_from_forgery

  before_filter :authenticate_user!
  before_filter :get_edition

  def get_edition
    @edition = Edition.first(:conditions => { :FriendlyName => params[:edition] } )
  end

end

现在我只想确保这是实现这一目标的最佳方式。

Answer 1

实际上，您可以执行以下操作：

my_var = "persons"
resources my_var.to_sym

字符串上的to_sym方法将其更改为符号

Answer 2

如果你不知道版本的可能值 - 那么你就不能使用似乎可能已经解决了这个问题的命名空间。

那就是说，我只是手工制作它们 - 你的情况似乎是理想的情况，不仅仅是资源，而是直接进入手工制作的道路。

Rails 3使用变量命名空间路由资源

2 个答案: