Question

我已经为hibernate使用了maven插件，并且它生成了实体类而没有识别与ID字段相关的序列，id字段被生成为BigDecimal ...现在即使我通过代码指向现有序列，如.. < / p>


@Entity
@javax.persistence.SequenceGenerator(

name = "SEQ_NATUREMASTER", sequenceName = "aop_teqachers_school_nature_id_seq")
@Table(name = "aop_teachers_school_nature_master", schema = "public", uniqueConstraints = @UniqueConstraint(columnNames = "school_nature"))
public class AopTeachersSchoolNatureMaster implements java.io.Serializable {

 /**
  * Above code is added after generating entity class
  */

 private BigDecimal id;

我收到错误


INFO : aop.web.teacher.controller.SchoolMasterInsertController - Attemped saving!testnature
Hibernate: select nextval ('aop_teqachers_school_nature_id_seq')
Dec 14, 2010 6:57:26 PM org.apache.catalina.core.StandardWrapperValve invoke
SEVERE: Servlet.service() for servlet appServlet threw exception
org.hibernate.id.IdentifierGenerationException: this id generator generates long, integer, short or string
 at org.hibernate.id.IdentifierGeneratorHelper.get(IdentifierGeneratorHelper.java:123)
 at org.hibernate.id.SequenceGenerator.generate(SequenceGenerator.java:101)
 at org.hibernate.id.SequenceHiLoGenerator.generate(SequenceHiLoGenerator.java:81)
 at org.hibernate.event.def.AbstractSaveEventListener.saveWithGeneratedId(AbstractSaveEventListener.java:122)
 at org.hibernate.ejb.event.EJB3PersistEventListener.saveWithGeneratedId(EJB3PersistEventListener.java:69)
 at org.hibernate.event.def.DefaultPersistEventListener.entityIsTransient(DefaultPersistEventListener.java:154)
 at org.hibernate.event.def.DefaultPersistEventListener.onPersist(DefaultPersistEventListener.java:110)
 at org.hibernate.event.def.DefaultPersistEventListener.onPersist(DefaultPersistEventListener.java:61)
 at org.hibernate.impl.SessionImpl.firePersist(SessionImpl.java:650)
 at org.hibernate.impl.SessionImpl.persist(SessionImpl.java:624)
 at org.hibernate.impl.SessionImpl.persist(SessionImpl.java:628)
 at org.hibernate.ejb.AbstractEntityManagerImpl.persist(AbstractEntityManagerImpl.java:308)

Answer 1

我不会使用小数ID。我真的认为你也不需要BigInteger。因此，请将其更改为int或long。（失败的原因是序列无法生成类型BigX）

hibernate中的JPA bigdecimal问题

1 个答案: