为了更多地了解C,过去两天我一直在玩它。我想开始研究C在运行时是如何构造的,所以,我构建了一个糟糕的程序,要求用户输入两个整数值,然后输出整数变量的内存位置。然后我想验证数据是否真的存在,我将程序暂停了getchar()以打开GDB并挖掘内存段以验证数据但是,这些位置的数据没有多大意义我。有人可以解释这里发生了什么。
#include <stdio.h>
void pause();
int main() {
int a, b;
printf("Please enter number one:");
scanf("%d", &a);
printf("Please enter number two:");
scanf("%d", &b);
printf("number one is %d, number two is %d\n", a, b);
// find the memory location of vairables:
printf("Address of 'a' %pn\n", &a);
printf("Address of 'b' %pn\n", &b);
pause();
}
void pause() {
printf("Please hit enter to continue...\n");
getchar();
getchar();
}
[josh@TestBox c_code]$ ./memory
Please enter number one:265
Please enter number two:875
number one is 265, number two is 875
Address of 'a' 0x7fff9851314cn
Address of 'b' 0x7fff98513148n
Please hit enter to continue...
(gdb) dump memory ~/dump2.hex 0x7fff98513148 0x7fff98513150
[josh@TestBox ~]$ xxd dump2.hex
0000000: 6b03 0000 0901 0000 k.......
答案 0 :(得分:9)
6b030000
和09010000
是little-endian(最低有效字节优先)。要以更自然的方式阅读它们,请颠倒字节的顺序:
6b030000
=&gt; 0000036b
=&gt;十进制875
09010000
=&gt; 00000109
=&gt;十进制265