Graphql解析嵌套字段上的函数未被调用

Question

使用此查询，在graphQL中，{ "query": "query ($requiredArg: String!, $anotherArg: String) { user(requiredArg: $requiredArg) { desiredSubfield(anotherArg: $anotherArg) { _id name} } }", "variables": { "requiredArg": "someString", "anotherArg": "anotherString" } } 上的解析函数未被调用，查询返回null。如何正确解析嵌套字段？

查询：

export default {
  type: userType,
  args: {
    requiredArg: {
      name: 'requiredArg',
      type: new GraphQLNonNull(GraphQLString),
    },
  fields: () => {
    return {
      desiredSubfield: {
        type: subfieldType,
        args: subfieldType.args,
        resolve(source, params, root, ast) {
          console.log('subfield resolve is hit');
          return fetchUser();
        },
      },
    };
  },
  resolve(source, params, root, ast) {
    console.log('in main resolve');
  }
};

相关对象：

{{1}}

Answer 1

好吧，看起来我想通了（叹息）

问题是我为非嵌套字段写的虚拟解析函数没有返回。看到修复：

export default {
  type: userType,
  args: {
    requiredArg: {
      name: 'requiredArg',
      type: new GraphQLNonNull(GraphQLString),
    },
  fields: () => {
    return {
      desiredSubfield: {
        type: subfieldType,
        args: subfieldType.args,
        resolve(source, params, root, ast) {
          console.log('subfield resolve is hit');
          return fetchUser();
        },
      },
    };
  },
  resolve(source, params, root, ast) {
    console.log('in main resolve');
    return true;
  }
};

我会把这个留在这里以防万一其他人遇到同样的事情。