Question

我有一个使用Spring安全OAuth2保护的Vaadin应用程序。这种方法很好，除了偶尔请求PUSH或HEARTBEAT端点首先请求并因此触发auth进程并且用户最终在错误的页面上（这些端点不应该被用户直接访问）。

对这些端点上的permitAll()进行简单但不安全的修复。然而，由于这构成威胁，我需要关闭这个洞。

要做到这一点，我想解析并可能编辑请求网址，然后在成功验证时重定向到它。我该怎么做呢？

我猜我需要在链中的某处添加一个过滤器来拦截请求并对其进行编辑。但我不知道在哪里。

这是我的客户：

@Configuration
@EnableOAuth2Sso
public class OAuthConfig extends WebSecurityConfigurerAdapter
{

    @Override
    protected void configure(HttpSecurity http) throws Exception
    {
        http.csrf().disable()
                .authorizeRequests()
                .antMatchers("/login**").permitAll()
                .antMatchers("/vaadinServlet/PUSH/**").permitAll()          //todo fix this hole
                .antMatchers("/vaadinServlet/HEARTBEAT/**").permitAll()      //todo fix this hole
                .anyRequest().authenticated()
                .and()
                .logout()
                .logoutSuccessUrl("/")
                .logoutRequestMatcher(new AntPathRequestMatcher("/logout"));

    }

    @Override
    public void configure(WebSecurity web) throws Exception
    {
        web.ignoring().antMatchers("/css/*").antMatchers("/VAADIN/**"); // Static resources are ignored
    }

}

服务器：

@Configuration
@EnableAuthorizationServer
public class OAuth2Config extends AuthorizationServerConfigurerAdapter
{
//jwt token stuff & my own client/auth providers. Should not be important.
...
}

服务器登录表单：

@Configuration
public class WebSecurityConfig extends WebSecurityConfigurerAdapter
{

    @Autowired
    private RestAuthenticationProvider authenticationProvider;

    @Override
    public void configure(AuthenticationManagerBuilder auth) throws Exception
    {
        auth.authenticationProvider(authenticationProvider);
    }

    @Override
    protected void configure(HttpSecurity http) throws Exception
    {
        http
                .authorizeRequests()
                .antMatchers(HttpMethod.GET, "/forgetPassword*").permitAll()
                .antMatchers(HttpMethod.POST,"/user/resetPassword*").permitAll()
                .antMatchers(HttpMethod.GET,"/user/changePassword*").permitAll()
                .antMatchers("/user/updatePassword*", "/user/savePassword*", "/updatePassword*")
                .hasAnyAuthority("CHANGE_PASSWORD_PRIVILEGE","ROLE_USER")
                .anyRequest().authenticated()
                .and()
                    .formLogin()
                    .loginPage("/login")
                    .permitAll()
                .and()
                    .csrf().csrfTokenRepository(csrfTokenRepository());
    }

    private CsrfTokenRepository csrfTokenRepository()
    {
        HttpSessionCsrfTokenRepository repository = new HttpSessionCsrfTokenRepository();
        repository.setHeaderName("X-XSRF-TOKEN");
        return repository;
    }

}

Answer 1

只需在项目中添加一些实现

1：创建身份验证失败处理程序

@Component
public class CustomAuthenticationFailureHandler extends SimpleUrlAuthenticationFailureHandler {


    @Override
    public void onAuthenticationFailure(HttpServletRequest request, HttpServletResponse response, AuthenticationException exception) throws IOException, ServletException {
        System.out.print("here failure");



        String s=request.getParameter("username");
        setDefaultFailureUrl("/login?error&username="+s);
        super.onAuthenticationFailure(request,response,exception);
    }

}

2：身份验证成功处理程序

@Component
public class CustomAuthenticationSuccessHandler extends SimpleUrlAuthenticationSuccessHandler {

    @Override
    public void onAuthenticationSuccess(HttpServletRequest request , HttpServletResponse response, Authentication authentication) throws IOException, ServletException {
        /* custom Block 
Do any thing here
  */

        setDefaultTargetUrl("/home/");
        super.onAuthenticationSuccess(request,response,authentication);
    }
}

3：访问请求入口点

@Component
public class CustomAuthenticationEntryPoint implements AuthenticationEntryPoint {
    @Override
    public void commence(HttpServletRequest httpServletRequest, HttpServletResponse httpServletResponse, AuthenticationException e) throws IOException, ServletException {
        System.out.print("Unauthorized Access");

        httpServletResponse.sendError(HttpServletResponse.SC_UNAUTHORIZED);
    }
}

根据您的要求实施组件。

spring security oauth2在重定向之前操作请求url

1 个答案: