Question

我正在创建一个包含大量字段的表单。我担心的是我想上传10kb的jpg文件以及其他HTML表单数据。

根据我的搜索，我还没有看到任何解释AngulaJS文件上传的帖子以及其他数据。请帮我做同样的事。在Angular控制器中创建对象时，我无法获得 fileUpload路径。这就是为什么它显示为undefine。代码如下： -

PS - 由于时间不足，我使用了表格标签。

HTML代码

<div id="wrapper">
<form>
<table>
    <thead>
        <tr>
            <td>Add Record</td>
            <td style="text-align:right"><a href="#/list" style="color:#000;">Back</a></td>
        </tr>
    </thead>
    <tbody>
        <tr>
            <td>Name</td>
            <td><input type="text" value="" id="name" tabindex="1" placeholder="Enter Name" ng-model="person.name" name="name"  /> </td>
        </tr>
        <tr>
            <td>Extn</td>
            <td><input type="text" value="" id="extn" tabindex="2" placeholder="Enter Extn" ng-model="person.extn" name="extn"   /> </td>
        </tr>
        <tr>
            <td>Designation</td>
            <td><input type="text" value="" id="designation" tabindex="3" placeholder="Enter Designation" ng-model="person.designation" name="designation"   /> </td>
        </tr>
        <tr>
            <td>mobile</td>
            <td><input type="text" value="" id="mobile" tabindex="4" placeholder="Enter Mobile" ng-model="person.mobile" name="mobile"   /> </td>
        </tr>
        <tr>
            <td>email</td>
            <td><input type="text" value="" id="email" tabindex="5" placeholder="Enter Email" ng-model="person.email" name="email"   /> </td>
        </tr>
        <tr>
            <td>upload file</td>
            <td><input  type="file" id="uploadFile" name="uploadFile" tabindex="6" ng-mode="person.fileUpload"   /> </td>
        </tr>
        <tr>
            <td></td>
            <td><input type="button" value="Submit" id="submitbtn" tabindex="7" ng-click="save(person)"/> </td>
        </tr>
    </tbody>
</table>
</form>

AngularJS

angular
.module("addressBook",['ngRoute'])
.controller('addController', ['$scope','$location','$rootScope','$http', function(scope,location,rootScope,http){

    scope.save = function (item){
        var personData = {
            'name' : scope.person.name, 
            'extn' : scope.person.extn, 
            'designation' : scope.person.designation, 
            'mobile' : scope.person.mobile, 
            'email' : scope.person.email,
            'fileUpload' : scope.person.fileUpload
        };

        if(typeof rootScope.crew === 'undefined'){
            rootScope.crew = [];
        }
        debugger;
        console.log(personData);
        http.post("server/insert.php",personData).success(function(data, status, headers, config){              
            scope.person = personData;
            //rootScope.crew.push(scope.person);
            location.path("/admin");
        })

    }
}]);

PHP代码

<?php
    include 'conn.php';
    $data = json_decode(file_get_contents("php://input"));

    $name = mysql_real_escape_string($data->name);
    $extn = mysql_real_escape_string($data->extn);
    $designation = mysql_real_escape_string($data->designation);
    $mobile = mysql_real_escape_string($data->mobile);
    $email = mysql_real_escape_string($data->email);


    echo $query = "INSERT INTO employee (`name`,`extn`,`designation`,`mobile`,`email`) VALUES ('$name', '$extn', '$designation', '$mobile' , '$email')";
    mysql_query($query);
    Print "Your information has been successfully added to the database.";  
?>

Answer 1

您可以使用Lightweight Angular指令上传带有输入字段的文件 https://github.com/danialfarid/ng-file-upload

使用PHP和MySql上传表单数据的AngularJS文件

1 个答案: