Question

有没有办法从zip解压缩一个文件？我正在使用基于response的 How to get Inno Setup to unzip a file it installed (all as part of the one installation process)代码，非常适合解压缩，但不知道如何解压缩单个文件：

[Code]:

const
  NO_PROGRESS_BOX = 4;
  RESPOND_YES_TO_ALL = 16;

procedure UnZip(ZipPath, TargetPath: string); 
var
  Shell: Variant;
  ZipFile: Variant;
  TargetFolder: Variant;
begin
  Shell := CreateOleObject('Shell.Application');

  ZipFile := Shell.NameSpace(ZipPath);
  if VarIsClear(ZipFile) then
    RaiseException(Format('ZIP file "%s" does not exist or cannot be opened', [ZipPath]));

  TargetFolder := Shell.NameSpace(TargetPath);
  if VarIsClear(TargetFolder) then
    RaiseException(Format('Target path "%s" does not exist', [TargetPath]));

  TargetFolder.CopyHere(ZipFile.Items, NO_PROGRESS_BOX or RESPOND_YES_TO_ALL);
end;

Answer 1

使用Folder.ParseName检索对ZIP存档＆＃34;文件夹＆＃34;中特定文件的引用。然后将该引用传递给Folder.CopyHere以提取它。

const
  NO_PROGRESS_BOX = 4;
  RESPOND_YES_TO_ALL = 16;

procedure UnZip(ZipPath, FileName, TargetPath: string); 
var
  Shell: Variant;
  ZipFile: Variant;
  Item: Variant;
  TargetFolder: Variant;
begin
  Shell := CreateOleObject('Shell.Application');

  ZipFile := Shell.NameSpace(ZipPath);
  if VarIsClear(ZipFile) then
    RaiseException(Format('ZIP file "%s" does not exist or cannot be opened', [ZipPath]));

  Item := ZipFile.ParseName(FileName);
  if VarIsClear(Item) then
    RaiseException(Format('ZIP file "%s" does not contain file "%s"', [ZipPath, FileName]));

  TargetFolder := Shell.NameSpace(TargetPath);
  if VarIsClear(TargetFolder) then
    RaiseException(Format('Target path "%s" does not exist', [TargetPath]));

  TargetFolder.CopyHere(Item, NO_PROGRESS_BOX or RESPOND_YES_TO_ALL);
end;

Answer 2

我发现了一种有效的方式，而不是我所期望的但功能正常。

UnZip(AppFolder+'\modulos\seimpresoras-2.2.zip', tmpFolder); 
FileCopy(tmpFolder+'\seimpresoras\resources\default.properties', AppFolder+'\printers.properties', False);

如何让Inno Setup解压缩单个文件？

2 个答案: