Question

我正在制作一个简单的GUI，我现在的目标是让用户选择一个选项（运动学或电力），然后他们会按下按钮进入他们选择的一个新屏幕。目前，无论选择哪个按钮，按钮都会做同样的事情，我不知道如何改变它。我使用的是Python 3.6.1

from tkinter import *
import tkinter.font

bg_color1 = "#008B8B"

abc = Tk()

abc.title("Physics Problem Solver")
abc.rowconfigure(0, weight=1)
abc.columnconfigure(0, weight=1)

helvetica_bold_16 = tkinter.font.Font(
    root = abc, 
    family="Helvetica",
    weight="bold",
    size=16)

helvetica_bold_12 = tkinter.font.Font(
    root = abc,
    family="Helvetica",
    weight="bold",
    size=12)

app = Frame(abc,
    bd=6,
    relief="groove",
    bg=bg_color1)
app.rowconfigure(0, weight=1)
app.columnconfigure(0, weight=1)
app.grid(sticky=N+S+E+W)

msg1 = Message(app, 
    text = "Welcome to the Physics Problem Solver!",
    font=helvetica_bold_16,
    bg=bg_color1,
    fg="white",
    justify="center",
    relief="flat")
msg1.grid(pady=15)

def callback1():
    toplevel = Toplevel()
    toplevel.title("Window 2")
    toplevel.focus_set()

optionList = ("Kinematics",
    "Electricity")
om1v= StringVar()
om1v.set(optionList[0])

om1 = OptionMenu(app,
    om1v,
    "Kinematics",
    "Electricity")
om1.grid(pady=20)

b1= Button(app, 
    text="Go!",
    width=5,
    activebackground="#007070",
    activeforeground="#00ACAC",
    fg="black", 
    justify="center",
    font=helvetica_bold_12,
    relief="raised",
    command=callback1)
b1.grid(pady=20)

abc.mainloop()

Answer 1

你没什么需要做的。在你的回调中，你可以获得选项菜单的值，然后做任何合适的事情。

def callback1():
    if om1v.get() == "Kinematics":
        do_kinematics
    else:
        do_electricity()

使用Python和Tkinter，如何根据选项菜单中选择的选项，按下按钮做不同的事情？

1 个答案: