Question

我有一个简单的程序，它将浮点数x提升到整数n的幂和。我添加了一个while循环来重复提供适当输入的过程（这里＆＃39; Y＆＃39;同意）。但是，当我在scanf中键入任何任何字符时（＆＃34;％c＆＃34;，anwser）;程序失败并关闭。有什么想法吗？

float x;
 char *anwser='Y';
 int n,k;
 while (anwser=='Y'){
   printf("Give floating point number x to be raised at the power of n \n ");
   scanf("%f%d",&x,&n);
   printf(" \n result : %f",power(x,n));
   printf("\nDo again?? ");
   scanf(" %c",anwser);
  }

float power(float x , int n){
     int i;
     float pow=1;
     for(i=0;i<n;i++) pow*=x;
     return pow;
}

Answer 1

您不需要char*来存储像'Y'这样的字符。这是你的工作代码，有很少的mod：

 #include <stdio.h>

 int main(void)
 {
     double base;
     size_t exp;
     double res = 1;
     char answer;
     do {
         printf("Give floating point number x to be raised at the power of n: \n");
         scanf(" %lf%zu", &base, &exp);
         for (size_t i = 0; i < exp; i++) {
             res *= base;
         }
         printf("Result: %lf\n", res);
         printf("Do you want repeat? (y/Y or n/N)\n");
         scanf(" %c", &answer);
         res = 1;
     }while (answer == 'Y' || answer == 'y');
     return 0;
 }

C：使用scanf输入字符

1 个答案: