Question

我正在尝试通过引用解析JSON。我试着做这些例子，但没有输出信息。 get-query的结果是一个未解析的字符串。我如何获得信息？

截图：

<html ng-app="expeditionApp">
<head>
    <meta charset="utf-8">
    <title>Expedition</title>
    <link rel="stylesheet" href="https://maxcdn.bootstrapcdn.com/bootstrap/3.3.5/css/bootstrap.min.css">
    <script src="https://ajax.googleapis.com/ajax/libs/angularjs/1.4.7/angular.min.js"></script>

    <script>
        var expeditionApp = angular.module('expeditionApp', []);
        expeditionApp.controller('expeditionCtrl', function ($scope, $http)
        {



            $http.get('http://localhost:3030/expedition/query?query=PREFIX exp: <http://sparql.sstu.ru:3030/expedition/> SELECT ?About ?RecDate ?LinkToVideo ?Duration WHERE {?video exp:hasVideoAbout ?About. ?video exp:hasRecDate ?RecDate. ?video exp:hasLinkToVideo ?LinkToVideo. ?video exp:hasDuration ?Duration.}')
            .success(function(response) {
                $scope.var = response;
                console.log(response)
            })
            .error(function(response) {
                alert(response);
                console.log('Error: ' + response);
            });



        });
    </script>

</head>
<body ng-controller="expeditionCtrl">
    <h2>Example</h2>

        <pre>{{var}}</pre>

        <table class="table table-striped">
            <tr>
                <th>About</th>
                <th>RecDate</th>
                <th>LinkToVideo</th>
                <th>Duration</th>
            </tr>
            <tr ng-repeat="item in var.data  | orderBy: 'subject' ">
                <td>{{item.About}}</td>
                <td>{{item.RecDate}}</td>
                <td>{{item.LinkToVideo}}</td>
                <td>{{item.Duration}}</td>
            </tr>
      </table>
</body>

Answer 1

您不能使用$ scope.var，var是关键字因此无法使用，请更改变量名称并重试。

使用$ scope.allData = response;

如果响应正是您所分享的内容（屏幕截图），则行应为：

$ scope.allData = response.data.results.bindings;

Angular Json Parse。我做错了什么？

1 个答案: