我正在尝试从SQL服务器表中选择名称中都有短划线且大于32个字符。
我试过传递并引用但没有快乐。
我不太可能获得一个视图,只有读取权限。
proc sql;
drop table poss_gw1;
create table poss_gw1 as ( select * from cdb.'''form_Garden_waste_service_AF-Form-59fb9946-0f6e-4cd9-9b30-82fc5d96ec71'''n as agg);
quit;
proc sql;
connect to odbc(dsn=FirmstepReporting user=myname pwd=mypwd);
Create table work.tmp_gw as select * from connection to odbc (select * from "'form_Garden_waste_service_AF-Form-59fb9946-0f6e-4cd9-9b30-82fc5d96ec71'"n);
disconnect from odbc;
quit;
任何人都有任何想法?
答案 0 :(得分:2)
您需要在pass thru code中使用SQL Server语法。
create table work.tmp_gw as
select * from connection to odbc
(select *
from "form_Garden_waste_service_AF-Form-59fb9946-0f6e-4cd9-9b30-82fc5d96ec71"
);
如果您的变量名也对SAS无效,那么您还需要在pass thru代码中更改名称。
create table work.tmp_gw as
select * from connection to odbc
(select id
, "invalid-name" as valid_name
from "form_Garden_waste_service_AF-Form-59fb9946-0f6e-4cd9-9b30-82fc5d96ec71"
);