Question

我有一个密码对话框类，可以在想要删除或添加时询问密码。我想要的是可以一次又一次地重复使用这个对话框。
这是我的密码对话框类看起来像

public static class myPasswordDialog extends DialogFragment {

        @NonNull
        @Override
        public Dialog onCreateDialog(Bundle savedInstanceState) {
            AlertDialog.Builder builder = new AlertDialog.Builder(getActivity());
            LayoutInflater inflater = getActivity().getLayoutInflater();
            builder.setView(inflater.inflate(R.layout.password_dialog, null))
                    .setPositiveButton(R.string.delete, new DialogInterface.OnClickListener() {
                        @Override
                        public void onClick(DialogInterface dialog, int id) {
                            EditText passField = (EditText) ((AlertDialog) dialog).findViewById(R.id.password);
                            String password = passField.getText().toString();
                            if (password.matches(getString(R.string.pass_key))) {

                                //it should do something when it is correct
                            } else {
                                Toast.makeText(getActivity(), "Wrong Password", Toast.LENGTH_SHORT).show();
                            }
                        }
                    })
                    .setNegativeButton(R.string.cancel, new DialogInterface.OnClickListener() {
                        public void onClick(DialogInterface dialog, int id) {
                            dialog.dismiss();
                        }
                    });
            return builder.create();
        }
    }

这就是我调用密码类的方式

deletebtn.setOnClickListener(new View.OnClickListener() {
                    @Override
                    public void onClick(View v) {
                        myPasswordDialog mPasswordDialog = new myPasswordDialog();
                        mPasswordDialog.show(getFragmentManager(), "delete");
                    }
                });

我的想法是，如果片段输入正确或错误的密码，它将返回一个布尔值。但我能以什么方式做到这一点？

Answer 1

实施界面并设置回电

public static class MyPasswordDialog extends DialogFragment {
    public interface MyCallBack {
        public void onResult(boolean b);
    }

    public MyCallBack callBack;

    public MyPasswordDialog(MyCallBack callBack) {
        this.callBack = callBack;
    }

    @NonNull
    @Override
    public Dialog onCreateDialog(Bundle savedInstanceState) {
    // your code

    public void onClick(DialogInterface dialog, int id) {
        EditText passField = (EditText) ((AlertDialog) dialog).findViewById(R.id.password);
        String password = passField.getText().toString();
        if (password.matches(getString(R.string.pass_key))) {
            callBack.onResult(true); // pass false depends on condition
        } else {
        // code
        }
    }

    }

}

如何致电

deletebtn.setOnClickListener(new View.OnClickListener() {
                @Override
                public void onClick(View v) {
                    myPasswordDialog mPasswordDialog = new MyPasswordDialog(new MyPasswordDialog() {
                        @Override
                        public void onResult(boolean result) {
                        // result will be your ans
                        }
                    });
                    mPasswordDialog.show(getFragmentManager(), "delete");
                }
            });

如何使用DialogFragment返回true或false？

1 个答案: