Question

任何人都可以帮助我请计算2行或更多行记录见下面的查询。

SELECT docs_DocCode, SUM(invd_Qty) AS Total_IN
FROM   dbo.SI_InventoryDetail

WHERE  (docs_DocCode = 'D.C') AND (itm_ItemCode = '0101050000083') OR
       (docs_DocCode = 'STO') AND (itm_ItemCode = '0101050000083') OR
       (docs_DocCode = 'SAO') AND (itm_ItemCode = '0101050000083') OR
       (docs_DocCode = 'IOB') AND (itm_ItemCode = '0101050000083') OR
       (docs_DocCode = 'GRN') AND (itm_ItemCode = '0101050000083') OR
       (docs_DocCode = 'STI') AND (itm_ItemCode = '0101050000083') OR
       (docs_DocCode = 'SAI') AND (itm_ItemCode = '0101050000083') OR
       (docs_DocCode = 'SRN') AND (itm_ItemCode = '0101050000083') OR
       (docs_DocCode = 'PRN') AND (itm_ItemCode = '0101050000083')
GROUP BY docs_DocCode

ABove查询给我结果如下

dics_doccode   Total
D.C            328.00000000
GRN            205.00000000
IOB             96.00000000
SAI             66.00000000
SAO             51.00000000
SRN             14.00000000
STI            150.00000000
STO            150.00000000

现在我想加入（D.C + STI + SAI） - （GRN + STI + SAI + IOB）=一个值

我正在使用SQL SERVER 2000

Thankx

Answer 1

SELECT SUM(CASE
             WHEN docs_DocCode IN ('D.C', 'STI', 'SAI') THEN invd_Qty
             WHEN docs_DocCode IN ('GRN', 'STI', 'SAI', 'IOB') THEN -1 * invd_Qty
             ELSE 0
           END) AS One_Value
....

请注意，不会添加invd_Qty中不属于任何'D.C', 'STI', 'SAI', 'GRN', 'STI', 'SAI', 'IOB'的{{1}}。

PS：（D.C + STI + SAI ） - （ GRN + STI + SAI + IOB） - 我强调了无意义的（??）部分。它等于D.C. - (SAI + IOB)

Answer 2

我解决了我的问题感谢“Zerkms”以下是我的查询及其结果

选择Itm_itemcode，

    SUM(CASE WHEN docs_DocCode IN ('D.C', 'STO', 'SAO','PRN') THEN INVD_QTY END ) - 
    SUM(CASE WHEN docs_DocCode IN ('GRN', 'STI', 'SAI','SRN','IOB') THEN invd_Qty END) AS Qty

来自SI_InventoryDetail

其中Itm_itemcode ='0101050000083'

按Itm_itemcode分组

<强>结果

Item_code数量
0101050000083 -2.00000000

Thankx 勇敢的阿里khatri

计算b / w两行

2 个答案: