实际上我希望将已检查的行从一个div(表1)的表复制到另一个div的表(表2)。但是使用下面的脚本,当我检查多个复选框时,第一个选中的行将被最后检查的行替换。但我希望表格1的每个选中的行应该逐一列入表2中。
任何帮助表示赞赏。在此先感谢!!!
HTML
<div class="form-group" id="jqcc" >
<table id="order-table" name="order-table">
<tr>
<th>Select</th>
<th>Medication</th>
<th>Max Issue Limit</th>
</tr>
<tbody></tbody>
</table>
</div>
的Javascript
<script>
var tableControl = document.getElementById('order-table');
$('#jqcc').click(function () {
var result = []
var x1;
var tab;
var count = document.querySelectorAll('input[type="checkbox"]:checked').length;
$('input:checkbox:checked', tableControl).each(function () {
result.push($(this).parent().next().text() + "," + "<br>"); // refers title of product
$(this).closest('tr').find('input').each(function () {
x1 = $(this).val(); // refers price of product
})
tab = "<tr><td>" + result + "</td>";
tab += "<td>" + x1 + "</td>";
tab += "<td>" + x1 + " </td>";
tab += "<td><button type='button' onclick='deletePerson(this);' class='btn btn-default'> <span class='glyphicon glyphicon-remove' /></button></td>";
tab += "</tr>";
tab += "</tbody>"
$("#charges").html("<table id='peopleTable' class='table table-bordered table-condensed table-striped'><thead><tr><th>Description</th><th>Actual Amount</th> <th>Claim Amount</th> <th></th></tr></thead>" + tab + "</table>").show();
});
});
</script>
答案 0 :(得分:1)
您尝试更改:
<script>
var tableControl = document.getElementById('order-table');
$('#jqcc').click(function () {
var result = []
var x1;
var tab = "";
var count = document.querySelectorAll('input[type="checkbox"]:checked').length;
$("#charges").html("<table id='peopleTable' class='table table-bordered table-condensed table-striped'><thead><tr><th>Description</th><th>Actual Amount</th><th>Claim Amount</th> <th></th></tr></thead><tbody></tbody></table>").show();
$('input:checkbox:checked', tableControl).each(function () {
result.push($(this).parent().next().text() + "," + "<br>"); // refers title of product
$(this).closest('tr').find('input').each(function () {
x1 = $(this).val(); // refers price of product
//
tab = "<tr><td>" + result + "</td>";
tab += "<td>" + x1 + "</td>";
tab += "<td>" + x1 + " </td>";
tab += "<td><button type='button' onclick='deletePerson(this);' class='btn btn-default'> <span class='glyphicon glyphicon-remove' /></button></td>";
tab += "</tr>";
// append row html to table with id
$("#peopleTable").append(tab);
})
});
});