请帮助我将<form name="form" class="form-horizontal" novalidate>
<div class="form-group">
<label> Password: </label>
<input name="password" type="password"
placeholder="Password" required
ng-model="password"
ng-pattern="passwordRegex" />
</div>
<div ng-show="form.$submitted && form.password.$invalid">
<div ng-show="form.password.$error.required">
RequiredField</div>
<div ng-show="form.password.$error.pattern">
InvalidPassword</div>
</div>
<div class="form-group">
<label>ConfirmPassword:</label>
<input name="confirmPassword" type="password"
placeholder="ConfirmPassword" required
ng-model="confirmPassword"
ng-match="password" />
</div>
<div
ng-show="password != confirmPassword">
<div ng-show="form.confirmPassword.$error.match">
PasswordMismatch</div>
</div>
<div ng-show="form.$submitted &&
form.confirmPassword.$invalid">
<div ng-show="form.confirmPassword.$error.required">
RequiredField</div>
</div>
<button type="submit" ng-click="!form.$invalid &&
testCtrl.ok()">Ok</button>
</form>
转换为characters
格式
date
和as.date
没有工作......
strptime
然后我尝试使用代码:
c <- data.frame(id = c('1', '2', '3', '4'), Date = c("01-Feb-16","03-May-15","24-Oct-14","20-Oct-12"))
c$Date <- as.character(c$Date)
str(c)
或
c$Date <- as.Date(c$Date, format = "%d-%b-%y")
我已收到c$Date <- strptime(c$Date, '%d-%b-%y')
答案 0 :(得分:1)
您的日期采用德语格式,包含英文月份名称。在您的代码之前尝试此操作:
c <- data.frame(lapply(c, function(y) {
y <- gsub("May", "Mai", y); y
y <- gsub("Oct", "Okt", y); y
}))
c$Date1 <- as.Date(c$Date, format = "%d-%b-%y")
c$Date2 <- strptime(c$Date, '%d-%b-%y')
c
# id Date Date1 Date2
# 1 1 01-Feb-16 2016-02-01 2016-02-01
# 2 2 03-Mai-15 2015-05-03 2015-05-03
# 3 3 24-Okt-14 2014-10-24 2014-10-24
# 4 4 20-Okt-12 2012-10-20 2012-10-20