Question

我正在尝试向使用Eve作为框架的Rest API执行 POST 请求，但每当我尝试 POST 我的 JSON 我得到422错误说不可处理的实体。我的 GET 请求工作完全正常。这是我的Eve App的架构：

schema = { '_update': { 'type': 'datetime', 'minlength': 1, 'maxlength': 40, 'required': False, 'unique': True, }, 'Name': { 'type': 'string', 'minlength': 1, 'maxlength': 40, 'required': True, 'unique': False, }, 'FacebookId': { 'type': 'integer', 'minlength': 1, 'maxlength': 40, 'required': True, 'unique': True, }, 'HighScore': { 'type': 'integer', 'minlength': 1, 'maxlength': 40, 'required': True, 'unique': False, }, }

以下是我想发布的 JSON ：

{"_updated":null,"Name":"John Doe","FacebookId":"12453523434324123","HighScore":15}

以下是我尝试从客户端执行 POST 请求的方式：

IDictionary dict = Facebook.MiniJSON.Json.Deserialize(result.RawResult) as IDictionary; string name = dict["name"].ToString(); string id = dict["id"].ToString(); Player player = new Player(); player.FacebookId = id; player.Name = name; player.HighScore = (int) GameManager.Instance.Points; // Using Newtonsoft.Json to serialize var json = JsonConvert.SerializeObject(player); var headers = new Dictionary<string, string> {{"Content-Type", "application/json"}}; string url = "http://server.com/Players"; var encoding = new UTF8Encoding(); // Using Unity3d WWW class WWW www = new WWW(url, encoding.GetBytes(json), headers); StartCoroutine(WaitForRequest(www));

Answer 1

你让它变得如此复杂。首先，您需要一个帮助方法来调用您的服务。像这样的东西：

private static T Call<T>(string url, string body)
{
    var contentBytes = Encoding.UTF8.GetBytes(body);
    var request = (HttpWebRequest)WebRequest.Create(url);

    request.Timeout = 60 * 1000;
    request.ContentLength = contentBytes.Length;
    request.Method = "POST";
    request.ContentType = @"application/json";

    using (var requestWritter = request.GetRequestStream())
        requestWritter.Write(contentBytes, 0, (int)request.ContentLength);

    var responseString = string.Empty;
    var webResponse = (HttpWebResponse)request.GetResponse();
    var responseStream = webResponse.GetResponseStream();
    using (var reader = new StreamReader(responseStream))
        responseString = reader.ReadToEnd();

    return JsonConvert.DeserializeObject<T>(responseString);
}

然后简单地称之为：

var url = "http://server.com/Players";
var output=Call<youroutputtype>(url, json);

注意：我不知道你的输出类型是什么，所以我只想留给你。

422错误：Python POST请求

1 个答案: