for(int i = 0; i < Rect.rectangles.Count; i++)
{
if (Rect.rectangles[i].transform != null && Rect.rectangles[i].transform != "")
{
string firstNumber = Rect.rectangles[i].transform.Substring(18, 10);
string secondNumber = Rect.rectangles[i].transform.Substring(7, 10);
double a = Convert.ToDouble(firstNumber);
double b = Convert.ToDouble(secondNumber);
}
}
第一个数字是0.49052715,并且a的Convert.ToDouble很好。 但是当它走到界限时:
double b = Convert.ToDouble(secondNumber);
我得到例外:
FormatException:未知的char:,
但是secondNumber中的字符串中没有任何char / s:0.87142591
这是transform:matrix中的整个字符串(0.87142591,0.49052715,-0.49052715,0.87142591,0,0)
我提取前两个数字:0.49052715和0.87142591然后尝试将它们转换为double。但得到例外。
包含Rect.rectangles定义的代码:
private void ParseSvgMap()
{
XDocument document = XDocument.Load(@"C:\Users\mysvg\Documents\my.svg");
Rect.rectangles = document.Descendants().Where(x => x.Name.LocalName == "rect").Select(x => new Rect()
{
style = Rect.GetStyle((string)x.Attribute("style")),
id = (string)x.Attribute("id"),
width = (double)x.Attribute("width"),
height = (double)x.Attribute("width"),
x = (double?)x.Attribute("width"),
y = (double?)x.Attribute("width"),
transform = x.Attribute("transform") == null ? "" : (string)x.Attribute("transform")
}).ToList();
for(int i = 0; i < Rect.rectangles.Count; i++)
{
if (Rect.rectangles[i].transform != null && Rect.rectangles[i].transform != "")
{
string firstNumber = Rect.rectangles[i].transform.Substring(18, 10);
string secondNumber = Rect.rectangles[i].transform.Substring(7, 10);
double a = Convert.ToDouble(firstNumber);
double b = Convert.ToDouble(secondNumber);
float degree = FindDegree(a, b);
}
}
}
public static float FindDegree(double a, double b)
{
float value = (float)((System.Math.Atan2(a, b) / System.Math.PI) * 180f);
if (value < 0) value += 360f;
return value;
}
public class Rect
{
public static List<Rect> rectangles { get; set; }
public Dictionary<string, string> style { get; set; }
public string id { get; set; }
public double width { get; set; }
public double height { get; set; }
public double? x { get; set; }
public double? y { get; set; }
public string transform { get; set; }
public double degree { get; set; }
public static Dictionary<string, string> GetStyle(string styles)
{
string pattern = @"(?'name'[^:]+):(?'value'.*)";
string[] splitArray = styles.Split(new char[] { ';' });
Dictionary<string, string> style = splitArray.Select(x => Regex.Match(x, pattern))
.GroupBy(x => x.Groups["name"].Value, y => y.Groups["value"].Value)
.ToDictionary(x => x.Key, y => y.FirstOrDefault());
return style;
}
}
答案 0 :(得分:2)
.Substring(18, 10)
这样的代码是绝对脆弱的(正如你所发现的)是一个等待发生的事故。数字不保证长度相同。只需查看您提供的示例数据。
在尝试解析字符串之前,你应该使用类似正则表达式的字符串来提取字符串中的数字。
var regex = new Regex(@"matrix\((?<num>-?(?:\d|\.)+)(?:,(?<num>-?(?:\d|\.)+))*\)");
var data = "matrix(0.87142591,0.49052715,-0.49052715,0.87142591,0,0)";
var values = regex
.Matches(data)
.Cast<Match>()
.SelectMany(m => m.Groups["num"]
.Captures
.Cast<Capture>()
.Select(c=>c.Value))
.Select(double.Parse)
.ToList();
然后使用values[0]
和values[1]
选择您想要的数字。
答案 1 :(得分:1)
它注定要失败。 我会使用以下正则表达式:
string test = "matrix(0.1234,0.23233433,0.34,-3343,-3.33)";
Regex reg = new Regex("[-]?[0-9]+(\\.[0-9]+)?");
MatchCollection coll = reg.Matches(test);
答案 2 :(得分:0)
您可以按照以下方式编写方法:
public double fixString(string incoming)
{
Double a;
if(incoming.Contains(','))
{
string fixedNum = incoming.Remove(incoming.IndexOf(','));
a = Convert.ToDouble(fixedNum);
return a;
}
else
{
a = Convert.ToDouble(incoming);
return a;
}
}