Question

我写了一个程序，为用户生成随机数猜测。我正在努力捕捉所有可能的错误。唯一一个我似乎无法弄清楚的是这个。一开始我要求用户按Enter键继续游戏。如果程序输入字符串甚至是特殊字符和标点符号，程序就会捕获。我唯一无法阻止的是，如果他们输入一个数字，程序就会终止。这就是我所拥有的。问题出在try块的第一个while循环中。任何建议或帮助将不胜感激。提前谢谢。

from random import randint #imports randint from random class

cont = input('Press enter to continue')

while True:
    if cont != '':
        try:
            int(cont)
            str(cont)
            break
        except ValueError:
            print('Just hit enter')
            cont = input()
            continue
    elif cont == '':
        while True:

            randNum = randint(1, 100)
            print('Try guesssing a number between 1 and 100')
            num = input()

            while True:
                try:
                    int(num)
                    break
                except ValueError:
                    print('Please enter a number')
                    num = input()

                int(num)
            if num == randNum:
                print('Good job, ' + str(num) + ' is correct.')
            else:
            print('Sorry, the number was ' + str(randNum) + '.')

        print('Would you like to try again?')
        answer = input().lower()
        if answer == 'yes':
            continue
        elif answer == 'no':
            print('Thanks for playing')
            exit()
        else:
            while True:
                print('Please type yes or no')
                answer = input()
                if answer == 'yes':
                    break
                elif answer == 'no':
                    print('Thanks for playing.')
                    exit()

Answer 1

输入数字时会发生什么，程序会尝试将数字转换为int（有效），然后转换为str（也有效），之后会中断。相反，请尝试以下方法：

from random import randint #imports randint from random class

cont = input('Press enter to continue')

while cont != '':
    cont = input('Press enter to continue')

while True:

    randNum = randint(1, 100)
    print('Try guesssing a number between 1 and 100')
    num = input()

    while True:
        try:
            int(num)
            break
        except ValueError:
            print('Please enter a number')
            num = input()

        num = int(num)
    if num == randNum:
        print('Good job, ' + str(num) + ' is correct.')
    else:
    print('Sorry, the number was ' + str(randNum) + '.')

print('Would you like to try again?')
answer = input().lower()
if answer == 'yes':
    continue
elif answer == 'no':
    print('Thanks for playing')
    exit()
else:
    while True:
        print('Please type yes or no')
        answer = input()
        if answer == 'yes':
            break
        elif answer == 'no':
            print('Thanks for playing.')
            exit()

Answer 2

while True:
    if cont != '':
        try:
            int(cont)
            str(cont)
            break

它在这里做的是尝试将cont转换为int，如果成功则尝试将其转换为字符串（这实际上总是可行的）。如果成功，则会中断while循环并结束程序。在尝试解析它int(cont)时，除了int之外的任何其他场景，它会引发错误并继续执行您的程序。

一旦他按下进入续约。在输入文本之前，你没有理由证明他没有写东西。

Python catch int或str

2 个答案: