Question

我的代码遇到的问题是，我只在name表中使用相同search_db字段的多个结果显示1个按钮。 name字段具有不同的ID。我需要收集所有相同的fullnames。这是一个非常复杂的解释主题，这是我解释它的最佳方式。

这是我的源代码：

<?php
    include('connect.php');
?>
<!DOCTYPE html>
<html>
    <head>
        <meta name="viewport" content="width=device-width, initial-scale=1">
        <link rel="stylesheet" href="https://maxcdn.bootstrapcdn.com/bootstrap/3.3.7/css/bootstrap.min.css">
        <script src="https://ajax.googleapis.com/ajax/libs/jquery/3.2.1/jquery.min.js"></script>
        <script src="https://maxcdn.bootstrapcdn.com/bootstrap/3.3.7/js/bootstrap.min.js"></script>
        <title>Example</title>
    </head>
    <body>
        <form action="test.php" method="POST">
            <input type="text" name="value" placeholder="Hello" />
            <input type="submit" name="submit" value="Search" />
        </form><br />
        <?php
            if(isset($_POST['submit']))
            {
                $value = htmlspecialchars($_POST['value']);
                $stmt = $pdo->prepare("SELECT * FROM search_db WHERE fullname = :fullname");
                $stmt -> execute(array(':fullname' => $value));
                $result = $stmt -> fetchAll();
                foreach($result as $row)
                {
                    $id = $row['id'];
                    $db_name = $row['name'];
                    $name = $row['fullname'];
                    $username = $row['username'];
                    $password = $row['password'];
                    $dob = $row['date'];
                    $email = $row['email'];

                    $test =  '<p >'.$name. ' ' . $password . '</p>';
                }
                echo '<button data-toggle="collapse" data-target="#test">'. count($result) .' Results Found</button><br />';
                echo '<div id="test" class="collapse">'. $test . '</div>';
            }
        ?>
    </body>
</html>

Answer 1

我认为你需要连接php变量形式的值，你可以在单个按钮中显示所有值检查$test变量

if(isset($_POST['submit']))
            {
                $test='';
                $value = htmlspecialchars($_POST['value']);
                $stmt = $pdo->prepare("SELECT * FROM search_db WHERE fullname = :fullname");
                $stmt -> execute(array(':fullname' => $value));
                $result = $stmt -> fetchAll();
                foreach($result as $row)
                {
                    $id = $row['id'];
                    $db_name = $row['name'];
                    $name = $row['fullname'];
                    $username = $row['username'];
                    $password = $row['password'];
                    $dob = $row['date'];
                    $email = $row['email'];

                    $test .=  '<p >'.$name. ' ' . $password . '</p><br>';
                }

Answer 2

有一些有用的PHP数组函数可以帮助计算值并删除重复项。

http://php.net/manual/en/function.array-count-values.php

http://php.net/manual/en/function.array-unique.php

<?php
    if(isset($_POST['submit']))
    {
        $value = htmlspecialchars($_POST['value']);
        $stmt = $pdo->prepare("SELECT * FROM search_db WHERE fullname = :fullname");
        $stmt -> execute(array(':fullname' => $value));
        $result = $stmt -> fetchAll();

        $namesArr = array(); //create empty array

        foreach($result as $row)
        {
            $id = $row['id'];
            $db_name = $row['name'];
            $name = $row['fullname'];
            $username = $row['username'];
            $password = $row['password'];
            $dob = $row['date'];
            $email = $row['email'];

            $test =  '<p >'.$name. ' ' . $password . '</p>';
            array_push($namesArr, $name);   //push each name into new array
        }
        $uniqueNamesArr = array_unique($namesArr);    //http://php.net/manual/en/function.array-unique.php
        $nameCounts = array_count_values($namesArr);  //http://php.net/manual/en/function.array-count-values.php
        foreach( $uniqueNamesArr as $uniqueName ) {
            echo '<div id="' . $uniqueName . '" class="collapse">'. $uniqueName . '</div>';
            echo '<button data-toggle="collapse" data-target="#' . $uniqueName . '">'. $nameCounts[$uniqueName] .' Results Found</button><br />';
        }
    }
?>

使用1个按钮显示多个结果

2 个答案: