Question

我有句子定义随机组合的模板：

I like dogs/cats    
I want to eat today/(the next day)

我尝试使用正则表达式：

m = re.search(r'(?P<list>[A-Za-z]+/([A-Za-z]+)+)', sentence)
words = m.group('list').split('/')
combs = [comb for comb in [sentence.replace(m.group('list'), w) for w in words]]

对于第一句话，我得到了['i like dogs', 'i like cats']这就是我想要的。对于第二句，re.search返回None。我想得到的是['I want to eat today', 'I want to eat the next day']。

我如何更改正则表达式？

Answer 1

（我今天想吃）* |（第二天）

正则表达式会选择你想要的文字......

Answer 2

r'(?P<list>[A-Za-z]+/([a-zA-Z]+|\(.+?\)))''

([a-zA-Z]+|\(.+?\))匹配＆＃34; word＆＃34;等字符串或者＆＃34;（某些词）＆＃34;。它也匹配＆＃34;（）＆＃34;，我们需要删除标题＆＃34;（＆＃34;和尾随＆＃34;）＆＃34;使用strip。

m = re.search(r'(?P<list>[A-Za-z]+/([a-zA-Z]+|\(.+?\)))', sentence)
words = m.group('list').split('/')
combs = [comb for comb in [sentence.replace(m.group('list'), w.strip('()')) for w in words]]

Answer 3

使用以下代码，您将获得类似

的内容

> sentence = 'I want to eat today/(the next day)' m =
> re.search(r'(?P<list>[A-Za-z]+/([A-Za-z]+|(\(.*?\))))', sentence)
> print m.group('list') words = m.group('list').split('/') combs = [comb
> for comb in [sentence.replace(m.group('list'), w) for w in words]]
> print combs

['I want to eat today', 'I want to eat (the next day)'

你可以进行额外的处理，以摆脱应该很容易的额外括号

从正则表达式创建所有组合

3 个答案: