具有COUNT值的MySQL JOIN表

Question

我的数据库中有以下表格。我只列出了可用于加入的重要列。

我需要得到以下输出

目前，我对每个 COUNT 值使用两个单独的查询

对于已分配的许可

select
    products.id,products.name,COUNT(assigned_licenses.id)
from
    deployment_users
inner join
    assigned_licenses 
on
    deployment_users.id = assigned_licenses.deployment_user_id
inner join
    products
on
    assigned_licenses.id = products.id
and
    deployment_users.customer_id = 10
group by
    assigned_licenses.id
;

总许可证

select
    products.id,products.name,COUNT(total_licenses.id)
from
    customers
inner join
    total_licenses
on
    customers.iccode = licenses.iccode
inner join
    products
on
    total_licenses.id = products.id
and
    customers.id = 10
group by
    total_licenses.id
;

由于需要列出超过1,000种产品，我想将它们合并为一个查询。我该怎么做？

Answer 1

您的规范留有一定的解释空间（例如，用户是否可以分配没有总许可证的许可证？如果是，我的查询将失败。）但我会继续这样做。

SELECT
    products.id,
    products.name,
    Count(Distinct total_licenses.id) As CountTotalLicenses,
    Count(Distinct assigned_liceses.deployment_users_id) As CountAssignedLicenses
FROM products
    LEFT JOIN total_licenses ON total_licenses.products_id = products.id
    LEFT JOIN customers ON customers.iccode = total_licenses.customers_iccode
    LEFT JOIN assigned_licenses ON assigned_liceses.total_licenses_id = total_licenses.id
WHERE
    customers.id = 10
GROUP BY
    products.id,
    products.name

对于将来，如果您可以将代码粘贴为代码而不是图像，那将是非常棒的。人们无法简单地复制代码的粘贴片段，并且必须再次键入所有内容...

Answer 2

尝试加入两个查询

SELECT * FROM (
   (First Query) as assigned_licn 
   INNER JOIN 
   (Second Query) as total_licn
   USING (id)
);