jdbc java

Question

   PreparedStatement predstaveFilmaStavek = con.prepareStatement("select shows_id from shows where movies_movie_id=?");
    predstaveFilmaStavek.setInt(1, bazniIDfilma);
    ResultSet predstaveFilma = predstaveFilmaStavek.executeQuery();
    ArrayList<Show> predstave = new ArrayList<Show>();
    while (predstaveFilma.next()) {
        predstave.add(new ShowDao().selectShow(predstaveFilma.getInt(1)));
    }

这给了我以下错误：

un. 03, 2017 1:06:18 PM org.apache.catalina.core.StandardWrapperValve invoke
SEVERE: Servlet.service() for servlet [jsp] in context with path [/kino] threw exception [An exception occurred processing JSP page /filmXML.jsp at line 17

14:     ResultSet predstaveFilma = predstaveFilmaStavek.executeQuery();
15:     ArrayList<Show> predstave = new ArrayList<Show>();
16:     while (predstaveFilma.next()) {
17:         predstave.add(new ShowDao().selectShow(predstaveFilma.getInt(1)));
18:     }
19: %>
20: 


Stacktrace:] with root cause
com.mysql.jdbc.exceptions.jdbc4.MySQLSyntaxErrorException: Unknown column 'id' in 'where clause'
    at sun.reflect.NativeConstructorAccessorImpl.newInstance0(Native Method)

我在db中有collumn movies_movie_id ...所以给出了什么？

我必须在这里输入更多的单词，这样我的任务才能被编辑......-.-

创建表的MySQL定义为：

  CREATE TABLE shows (
  `shows_id` INT auto_increment,
  `show_id` VARCHAR(18) NOT NULL,
  `date_time` datetime NOT NULL,
  `city` VARCHAR(45) NOT NULL,
  `center` VARCHAR(45) NOT NULL,
  `theater` VARCHAR(45) NOT NULL,
  `movies_movie_id` int NOT NULL,
  PRIMARY KEY (`shows_id`));

ALTER TABLE shows
ADD CONSTRAINT fk_shows_movies FOREIGN KEY
(`movies_movie_id`) REFERENCES movies(`movies_id`);