我需要将父子记录放在一个列中,并将其放在具有该ID的其他表中。和 我试过这个:
select parent.Parent,child1.child1,Child2.child2
from parent
join Child1 on child1.ParentIdId=parent.ParentID
join Child2 on child1.child1Id=child2.child1Id`
Create table parent (ParentID int, Parent varchar(10))
Create table Child1 (child1Id int, child1 varchar(10), ParentIdId int)
Create table Child2 (child2Id int, child2 varchar(10), child1Id int)
insert into parent values(10,'Sony'),(20,'Apple'),(30,'HTC'),(40,'Nexus')
insert into Child1 values(100,'Sony1',10),(200,'Sony2',10),(300,'Apple1',20),(400,'Apple2',20),(500,'HTC1',30),(600,'HTC2',30),
(700,'Nexus1',40),(800,'Nexus2',40)
insert into Child2 values(1000,'Sony11',100),(2000,'Sony22',100),(3000,'Apple11',200),(4000,'Apple22',200),(5000,'HTC11',300),(6000,'HTC22',300),
(7000,'Nexus11',400),(8000,'Nexus22',400)
我需要的输出:
Ids Products Parents
10 Sony null
20 Apple null
30 HTC null
40 Nexus null
100 Sony1 10
200 Sony2 10
300 Apple1 20
400 Apple2 20
500 HTC1 30
600 HTC2 30
700 Nexus2 40
800 Nexus2 40
1000 Sony11 100
2000 Sony22 100
3000 Apple11 200
4000 Apple22 200
5000 HTC11 300
6000 HTC22 300
7000 Nexus11 400
8000 Nexus22 400
答案 0 :(得分:2)
不使用union all和多个select语句
SELECT COALESCE(parent.ParentID, Child1.child1id, Child2.child2id),
COALESCE(Child2.child2, Child1.child1, parent.Parent),
COALESCE( Child1.ParentIdId, Child2.child1id) FROM parent
FULL JOIN Child1 on 1 = 2
FULL JOIN Child2 on 1 = 2
答案 1 :(得分:1)
您可能必须在3个不同的选择查询中执行此操作,如下所示
SELECT ParentIds as Ids,
Parent as Products,
CAST(NULL AS INT) AS Parent
INTO #Product
FROM Parent
UNION ALL
SELECT child1.child1id,
Child1.child1,
Child1.ParentId
FROM parent
INNER JOIN Child1 on child1.ParentIdId=parent.ParentID
UNION ALL
SELECT Child2.Child2Id,child2.child2,Child2.child1Id
FROM parent
INNER JOIN Child1 on child1.ParentIdId=parent.ParentID
INNER JOIN Child2 on child1.child1Id=child2.child1Id`
答案 2 :(得分:1)
我认为对于你的例子简单的联合一切都足够但我认为你正在寻找递归cte如下:
;with cte (Child, nam, parent) as
(
select * from child2
union all
select * from child1
union all
select *, null as Parent from parent
)
, cte2 as
(
select *, 0 as Levl from cte where parent is null
union all
select c1.*, c2.Levl + 1 as Levl from cte2 c2 join cte c1
on c2.child = c1.parent
)
select * from cte2
order by levl
我添加了Levl只是为了理解层次结构