Question

我是php开发的新手，可能这将是一个简单的答案，但我有这个致命的错误

致命错误：调用未定义的方法mysqli_stmt :: get_result（）在

在我的本地机器上运行良好，当前的PHP版本是5.6.11，在我的Web服务器上它给出了这个错误。我试图从5.4.45

将PHP版本改为5.6.30

这是我的代码

 $stmt = $this->conn->prepare("SELECT * FROM profile WHERE email_id = ?");
 $stmt->bind_param("s", $email);
 if ($stmt->execute()) {
     $user = $stmt->get_result()->fetch_assoc();//on this line I am having problem
     $stmt->close();
     return $user;
}

仅供参考：我的服务器上启用了mysqlnd

为什么它不能在我的网络服务器上运行？

请把我指向正确的方向

Answer 1

尝试以下代码。我根据你的问题量身定做了

  $stmt = $this->conn->prepare("SELECT * FROM profile WHERE email_id = ?");
    $stmt->bind_param('s', $email);
    $result = $stmt->execute();
   $stmt->store_result();//after this line we can output the number of rows if you need to check that as well
   $number_of_rows = $stmt->num_rows;
   $meta = $stmt->result_metadata();
   $parameters = array();
  $results = array();
  while ($field = $meta->fetch_field()) {
         $parameters[] = &$row[$field->name];
  }
  call_user_func_array(array($stmt, 'bind_result'), $parameters);
       while ($stmt->fetch()) {
             foreach ($row as $key => $val) {
                  $x[$key] = $val; //here we get the key => value (Column => Value)
                      }
                      $results[] = $x; //lets grab everything here
                  }
print_r($results);

调用未定义的方法mysqli_stmt :: get_result（）

1 个答案: