我遇到了一个小python函数的问题,目前我有这样的结构:
dict_conf = {'conf_storage':
{'option1':[
{'number':'20169800'},
{'name':'usb'},
{'description':'16gb'},
{'qty':'1'},
{'vendor=':'XLR'},
{'online':'Yes'}],
'option2':[
{'number':'20161789'},
{'name':'hardrive'},
{'description':'128gb'},
{'qty':'1'},
{'vendor=':'KBW'},
{'online':'NO'}]},
'conf_grph':
{'option1':[
{'number':'20170012'},
{'name':'HD_screen'},
{'description':'1080p'},
{'qty':'1'},
{'vendor=':'PWD'},
{'online':'Yes'}]}}
conf_type = raw_input("Enter the conf type: ")
option = raw_input("Enter the option")
我想找"数字"值,例如,如果用户输入:
conf_type = "conf_storage"
number = "20169800"
然后打印值和一条消息说:"您输入的是有效号码,它是:20169800"
我的想法是迭代并返回与用户输入的值相等的每个值。
如果我使用iteritems我得到每个元素然后我可以将它放入for循环但是之后我不知道如何进入包含字典的列表并检索&#34的值;数"键。
如果你有答案,请你解释一下,我的意思是你是怎么做的。
由于
答案 0 :(得分:1)
一个简单的解决方案可能是迭代所有元素。
conf_type = "conf_storage"
number = "20169800"
if dict_conf[conf_type]:
for key, value in dict_conf[conf_type].items():
for v in value:
for k,num in v.items():
if num == number:
print('found')
答案 1 :(得分:0)
这应该这样做:
print "You entered a valid number, it is:", dict_conf[conf_type][option][0]['number']
答案 2 :(得分:0)
将numbers
转换为列表并检查输入的number
是否在列表中,例如:
conf_type = "conf_storage"
number = "20169800"
if number in [option[0]['number'] for option in dict_conf[conf_type].values()]:
print("You entered a valid number, it is: {}".format(number))
# You entered a valid number, it is: 20169800
答案 3 :(得分:0)
这是完整的工作代码:
dict_conf = {'conf_storage':
{'option1':[
{'number':'20169800'},
{'name':'usb'},
{'description':'16gb'},
{'qty':'1'},
{'vendor=':'XLR'},
{'online':'Yes'}],
'option2':[
{'number':'20161789'},
{'name':'hardrive'},
{'description':'128gb'},
{'qty':'1'},
{'vendor=':'KBW'},
{'online':'NO'}]},
'conf_grph':
{'option1':[
{'number':'20170012'},
{'name':'HD_screen'},
{'description':'1080p'},
{'qty':'1'},
{'vendor=':'PWD'},
{'online':'Yes'}]}}
conf_type = raw_input("Enter the conf type: ")
option = raw_input("Enter the option: ")
number = raw_input("Enter the number for validation: ")
dict_options = dict_conf[conf_type]
option_list = dict_options[option]
for elem_dict in option_list:
if 'number' in elem_dict.keys():
if elem_dict['number'] == number:
print "You entered a valid number, it is: " + number