Question

我有一个列需要解析并插入到新表中。我非常接近获取我需要的数据，但我似乎无法正确获取语法。以下是我需要解析的数据格式：

包装单＃195，UID = Pkg-15094-195

包装单＃112，UID = Pkg-41251-241

我只需要装箱单编号。当然，它并不总是2个字符。

看起来比较简单，只需得到字符索引[＃]和[，] 然后从[＃] + 1的索引处开始[]， - [＃] - 1的长度。这是一个额外的减法，它搞砸了我的语法：

SELECT substring(IMG_FILE_DESCRIPTION, 
    CHARINDEX('#', IMG_FILE_DESCRIPTION) + 1,
    CHARINDEX(',', IMG_FILE_DESCRIPTION) - CHARINDEX('#', IMG_FILE_DESCRIPTION)
)
AS PKL
FROM MASTER_SCAN_IMAGE
where IMG_SCT_PKEY = '21'

这有效，但给了我太多。如果我尝试添加另一个减法，我会收到语法错误：

SELECT substring(IMG_FILE_DESCRIPTION, 
    CHARINDEX('#', IMG_FILE_DESCRIPTION) + 1,
    (CHARINDEX(',', IMG_FILE_DESCRIPTION) - CHARINDEX('#', IMG_FILE_DESCRIPTION)) -1
)
AS PKL
FROM MASTER_SCAN_IMAGE
where IMG_SCT_PKEY = '21'

Msg 537, Level 16, State 2, Line 1 Invalid length parameter passed to the LEFT or SUBSTRING function.

所以我认为我应该将长度值包装成单个变量，但它也会产生语法错误：

SELECT *
FROM MASTER_SCAN_IMAGE
DECLARE @length int = CHARINDEX(',', IMG_FILE_DESCRIPTION) - CHARINDEX('#', IMG_FILE_DESCRIPTION);

Msg 207, Level 16, State 1, Line 3
Invalid column name 'IMG_FILE_DESCRIPTION'.
Msg 207, Level 16, State 1, Line 3
Invalid column name 'IMG_FILE_DESCRIPTION'.

实际上我似乎无法使用CHARINDEX分配变量，我总是以相同的“无效列名”错误结束。

DECLARE @length bigint = CHARINDEX(',', IMG_FILE_DESCRIPTION);

Msg 207, Level 16, State 1, Line 3
Invalid column name 'IMG_FILE_DESCRIPTION'.

我是否使用int或bigint是charindex可以发送的两种返回类型。

Answer 1

使用此：

declare @column varchar(200) = 'Packing Slip #195, UID = Pkg-15094-195'


select RIGHT(LEFT(@column, CHARINDEX(',', @column)-1), CHARINDEX('#', REVERSE(LEFT(@column, CHARINDEX(',', @column)-1)))-1)

运行代码here。

Answer 2

如果您对TVF开放......请考虑以下事项。

厌倦了提取字符串，我修改了一个解析函数来加入两个非类似分隔符。

示例

Declare @YourTable table (ID int,IMG_FILE_DESCRIPTION varchar(max)) Insert Into @YourTable values (1,'Packing Slip #195, UID = Pkg-15094-195') ,(2,'Packing Slip #112, UID = Pkg-41251-241') ,(3,'Packing Slip #222, UID = Pkg-41251-241 and Slip #999') -- Notice two Packing Slips Select A.ID ,SlipNr = B.RetVal From @YourTable A Cross Apply [dbo].[udf-Str-Extract](A.IMG_FILE_DESCRIPTION+',','Slip #',',') B

<强>返回

ID SlipNr 1 195 2 112 3 222 <-- Notice multiple slips 3 999 <-- Notice multiple slips

感兴趣的UDF

CREATE FUNCTION [dbo].[udf-Str-Extract] (@String varchar(max),@Delimiter1 varchar(100),@Delimiter2 varchar(100)) Returns Table As Return ( with cte1(N) As (Select 1 From (Values(1),(1),(1),(1),(1),(1),(1),(1),(1),(1)) N(N)), cte2(N) As (Select Top (IsNull(DataLength(@String),0)) Row_Number() over (Order By (Select NULL)) From (Select N=1 From cte1 N1,cte1 N2,cte1 N3,cte1 N4,cte1 N5,cte1 N6) A ), cte3(N) As (Select 1 Union All Select t.N+DataLength(@Delimiter1) From cte2 t Where Substring(@String,t.N,DataLength(@Delimiter1)) = @Delimiter1), cte4(N,L) As (Select S.N,IsNull(NullIf(CharIndex(@Delimiter1,@String,s.N),0)-S.N,8000) From cte3 S) Select RetSeq = Row_Number() over (Order By N) ,RetPos = N ,RetVal = left(RetVal,charindex(@Delimiter2,RetVal)-1) From ( Select *,RetVal = Substring(@String, N, L) From cte4 ) A Where charindex(@Delimiter2,RetVal)>1 ) /* Max Length of String 1MM characters Declare @String varchar(max) = 'Dear [[FirstName]] [[LastName]], ...' Select * From [dbo].[udf-Str-Extract] (@String,'[[',']]') */

Answer 3

提取单据ID

   declare @column varchar(200) = 'Packing Slip #234234295, UID = Pkg-15094-195'


   select substring(@column,charindex('#',@column)+1,charindex(',',@column)-charindex('#',@column)-1)

从列中解析值并插入T-Sql中的新表

3 个答案: