Question

我正在编写一个脚本来将输出打印到html文件。我坚持我的输出格式。以下是我的代码：

#include <stdio.h>
#include <stdlib.h>
#include <string.h>

int addr_byte_0;
int addr_byte_1;

void scanner(int s) 
{
    char addr[200];
    int i;
    for (i = 0; i < 255; ++i) 
    {
        sprintf(addr, "%d.%d.%d.%d", addr_byte_0, addr_byte_1, s, i);
        printf("%s\n", addr);
    }
 }

int main() 
{
    int i;
    //printf("Enter the first byte of the address: ");
    scanf ("%d", &addr_byte_0);
    //printf("Enter the second byte of the address: ");
    scanf ("%d", &addr_byte_1);
    for (i = 0; i < 255; ++i) 
    {
        scanner(i);
    }

    return 0;
}

我希望我的输出是这样的：

def printTohtml(Alist):
    myfile = open('zip_files.html', 'w')
    html =  """<html>
    <head></head>
    <body><p></p>{htmlText}</body>
    </html>"""

    title = "Study - User - zip file -  Last date modified"
    myfile.write(html.format(htmlText = title))
    for newL in Alist:
        for j in newL:
            if j == newL[-1]:
                myfile.write(html.format(htmlText=j))
            else:
                message = j + ', '
                myfile.write(html.format(htmlText = message))
    myfile.close()

Alist =  [['123', 'user1', 'New Compressed (zipped) Folder.zip', '05-24-17'],
['123', 'user2', 'Iam.zip', '05-19-17'], ['abcd', 'Letsee.zip', '05-22-17'],
['Here', 'whichTwo.zip', '06-01-17']]

printTohtml(Alist)

但是我的代码在我自己的路线上给了我一切。有人可以帮帮我吗？

提前感谢您的帮助！

我的输出：

Study - User - zip file -  Last date modified
123, user1, New Compressed (zipped) Folder.zip, 05-24-17
123, user2, Iam.zip, 05-19-17
abcd, Letsee.zip, 05-22-17
Here, whichTwo.zip, 06-01-17

Answer 1

请改为尝试：

for newL in Alist:
        for j in newL:
            if j == newL[-1]:
                myfile.write(html.format(htmlText=j))
            else:
                message = message + ', ' + j
        myfile.write(html.format(htmlText = message))

对于newL中的每个元素，您需要将它们存储在“消息”中。完成每个newL的读取后，将'message'写入myfile。

Answer 2

每次迭代时，您的循环都在创建新的<head></head><body><p></p></body></html><html>。

此外，如果要删除段落之间的空格，请使用<style>p { margin: 0, !important; } </style>。

您可以尝试使用此功能，该功能可以提供所需的HTML输出。

def printTohtml(Alist, htmlfile):    
    html =  "<html>\n<head></head>\n<style>p { margin: 0 !important; }</style>\n<body>\n"

    title = "Study - User - zip file -  Last date modified"
    html += '\n<p>' + title + '</p>\n'

    for line in Alist:
        para = '<p>' + ', '.join(line) + '</p>\n'
        html += para

    with open(htmlfile, 'w') as f:
        f.write(html + "\n</body>\n</html>")

Alist =  [['123', 'user1', 'New Compressed (zipped) Folder.zip', '05-24-17'],
['123', 'user2', 'Iam.zip', '05-19-17'], ['abcd', 'Letsee.zip', '05-22-17'],
['Here', 'whichTwo.zip', '06-01-17']]

printTohtml(Alist, 'zip_files.html')

写入zip_files.html的标记是：

<html>
<head></head>
<style>p { margin: 0 !important; }</style>
<body>

<p>Study - User - zip file -  Last date modified</p>
<p>123, user1, New Compressed (zipped) Folder.zip, 05-24-17</p>
<p>123, user2, Iam.zip, 05-19-17</p>
<p>abcd, Letsee.zip, 05-22-17</p>
<p>Here, whichTwo.zip, 06-01-17</p>

</body>
</html>

页面显示以下输出：

Study - User - zip file - Last date modified    
123, user1, New Compressed (zipped) Folder.zip, 05-24-17    
123, user2, Iam.zip, 05-19-17    
abcd, Letsee.zip, 05-22-17    
Here, whichTwo.zip, 06-01-17

将python输出打印到html文件

2 个答案: