Question

我希望能够按照员工最新项目的有效日期对数据进行分组，包括部门和他们工作的经理。这是一个数据样本。

PROJ_TBL

+-------------+----------+----------------+
| EMPLOYEE_ID | EFF_DATE | EMPL_PROJECT   |
+-------------+----------+----------------+
| P1441       | 05/21/11 | IMC            |
| P1441       | 09/12/12 | BEEB           |
| P1441       | 09/23/12 | PRUD_FIN_SALES |
+-------------+----------+----------------+

EMPLOYEE_TBL

+-------------+--------------+---------+----------+
| EMPLOYEE_ID | PROJECT_MBR  | DEPT_NM | EFF_DATE |
+-------------+--------------+---------+----------+
| P1441       | BEN DEENEY   | ACCNT   | 02/09/08 |
| P1566       | LAURA FIELDS | ACCNT   | 05/03/10 |
| P2155       | PAUL DAVEY   | ACCNT   | 10/03/10 |
| P1441       | BEN DEENEY   | SALES   | 07/19/12 |
+-------------+--------------+---------+----------+

EMP_DPT_TBL

+-------------+---------------+---------+----------+
| EMPLOYEE_ID | MANAGER       | DEPT_NM | EFF_DATE |
+-------------+---------------+---------+----------+
| P1441       | BOB PAISLEY   | ACCNT   | 02/09/08 |
| P1441       | LINDA HARDY   | SALES   | 07/19/12 |
+-------------+---------------+---------+----------+

我对分区的使用不是很熟悉。我希望能够将其用于合并信息，以获取EMPLOYEE_ID P1441的当前数据。所需的输出是：

+-------------+---------+--------------+----------------+
| EMPLOYEE_ID | DEPT_NM | MANAGER      | PROJECT        |
+-------------+---------+--------------+----------------+
| P1441       | SALES   | LINDA HARDY  | PRUD_FIN_SALES |
+-------------+---------+--------------+----------------+

我能够获得各个表的正确当前记录，但将结果组合起来生成我想要的内容是有问题的。以下是查询...

-- Current Project
SELECT EMPL_PROJECT,
       EMPLOYEE_ID,
       EFF_DT
FROM   ( SELECT EMPL_PROJECT,
                EMPLOYEE_ID,
                EFF_DT,
                RANK() OVER ( PARTITION BY EMPLOYEE_ID
                              ORDER BY EFF_DT DESC) AS rk1
        FROM    PROJ_TBL ) t
WHERE  rk1 = 1

-- Current Department
SELECT DEPT_NM,
       EMPLOYEE_ID,
       EFF_DT
FROM   ( SELECT DEPT_NM,
                EMPLOYEE_ID,
                EFF_DT,
                RANK() OVER ( PARTITION BY EMPLOYEE_ID
                              ORDER BY EFF_DT DESC ) AS rk2 
         FROM   EMPLOYEE_TBL ) t
WHERE  rk2 = 1

-- Current Manager
SELECT MANAGER,
       EMPLOYEE_ID,
       EFF_DT
FROM   ( SELECT MANAGER,
                EMPLOYEE_ID,
                EFF_DT,
                RANK() OVER ( PARTITION BY EMPLOYEE_ID
                              ORDER BY EFF_DT DESC ) AS rk3
         FROM   EMP_DPT_TBL ) t
WHERE  rk3 = 1

如何使用EMPLOYEE_ID将这些组合成一个查询以生成报告？

Answer 1

这是你要找的吗？

SELECT DISTINCT
  EMPLOYEE_ID
  ,first_value(dept.dept_nm) over (partition by dept.employee_id order by dept.eff_date desc) as DEPT_NM
  ,first_value(dept.manager) over (partition by dept.employee_id order by dept.eff_date desc) as MANAGER
  ,first_value(proj.EMPL_PROJECT) over (partition by proj.employee_id order by proj.eff_date desc) as PROJECT
FROM
  EMPLOYEE_TBL emp
  INNER JOIN PROJ_TBL proj ON emp.EMPLOYEE_ID = proj.EMPLOYEE_ID
  INNER JOIN EMP_DPT_TBL dept on emp.EMPLOYEE_ID = dept.EMPLOYEE_ID

Oracle SQL分区和排名

1 个答案: