所以我正在开展一个学校项目，在那里我们需要建立一个租用电影的网站，而且我有点卡住了。
我得到错误：
致命错误：带有消息'SQLSTATE [42000]的未捕获异常'PDOException'：语法错误或访问冲突：1064 SQL语法中有错误;在第334行的/home/ubuntu/workspace/classes/video.php第1行'检查与您的MySQL服务器版本对应的手册，以获得正确的语法使用'WHERE idFilm = NULL）
（！）PDOException：SQLSTATE [42000]：语法错误或访问冲突：1064 SQL语法中有错误;在第334行的/home/ubuntu/workspace/classes/video.php第1行查看与您的MySQL服务器版本对应的手册，以获得正确使用的语法'WHERE idFilm = NULL）
这个想法是你可以创建一个新电影并添加一个或多个类型。我没有把流派连接到电影上。
所以我的代码是：
<?php
include('security.php');
$genre = $video->getAllGenre();
if(isset($_POST['submit'])){
$error = "";
//var_dump($_POST);
$target_dir = $_SERVER['DOCUMENT_ROOT'].'/images/covers/';
$temp = explode(".", $_FILES["file"]["name"]);
$fileName = $video->generateCoverName() .'.'. end($temp);
$target_file = $target_dir . $fileName;
//echo('Target file: '.$target_file);
$imageFileType = pathinfo($target_file,PATHINFO_EXTENSION);
$check = getimagesize($_FILES["file"]["tmp_name"]);
if($check == false) {
$error = "Bestand is geen foto.";
}
if ($_FILES["file"]["size"] > 50000000) {
$error = "Sorry, bestand is te groot.";
}
if($imageFileType != "jpg" && $imageFileType != "png" && $imageFileType != "jpeg"
&& $imageFileType != "gif" ) {
$error = "Sorry, alleen jpg, png, jpeg en gif zijn toegestaan.";
}
if (!$error) {
if (move_uploaded_file($_FILES["file"]["tmp_name"], $target_file)) {
//echo "The file ". $fileName. " has been uploaded.";
$video->genreToFilm($_POST['idFilm'], $_POST['idGenre']);
$video->newVideo($_POST['titel'], $_POST['aantal'], $fileName, $_POST['omschrijving'], $_POST['prijs']);
} else {
echo("Sorry, er was een probleem met het uploaden van uw bestand.");
}
} else {
print('<div class="alert alert-info fade-out">'.$error.'</div>');
}
}
?>
<div class="row">
<div class="col-xs-12 col-sm-12 col-md-12 loginborder">
<form role="form" method="post" action="" autocomplete="off" enctype="multipart/form-data">
<h2 class="loginhead">Film toevoegen</h2>
<hr>
<div class="registrationform">
<div class='row'>
<div class="form-group col-xs-12 col-sm-12 col-md-6">
<p>Titel:</p>
<input type="text" name="titel" id="titel" class="form-control input-lg" required value="<?php if(isset($error)){ print($_POST['titel']); } ?>" tabindex="1">
</div>
<div class="form-group col-12 col-xs-12 col-sm-12 col-md-6">
<p>Upload een coverfoto:</p>
<input type="file" name="file" id="file" required>
</div>
</div>
<div class='row'>
<div class="omschrijving form-group col-xs-12 col-sm-12 col-md-6">
<p>Omschrijving:</p>
<textarea style="resize: none;" name="omschrijving" rows="12" cols="50" placeholder="Omschrijving van de film..." required class="form-control"><?php if(isset($error)){ print($_POST['omschrijving']); }?></textarea>
</div>
<div class="form-group col-xs-12 col-sm-12 col-md-3">
<p>Aantal:</p>
<input type="number" name="aantal" id="aantal" class="form-control input-lg" min="0" max="1000" step="1" required value="<?php if(isset($error)){ print($_POST['aantal']); } ?>" tabindex="1">
</div>
<div class="form-group col-xs-12 col-sm-12 col-md-3">
<p>Prijs:</p>
<input type="number" name="prijs" id="prijs" class="form-control input-lg" min="0" max="9999.99" step="0.01" required value="<?php if(isset($error)){ print($_POST['aantal']); } ?>" tabindex="1">
</div>
<div class="form-group col-xs-12 col-sm-12 col-md-2">
<p>Genre 1:</p>
<select name="genre1" class="form-control input-lg">
<?php foreach ($genre as $gen) {
print(
'<option value='.$gen['idGenre'].'>'.$gen['genre'].'</option>');
} ?>
</select>
</div>
<div class="form-group col-xs-12 col-sm-12 col-md-2">
<p>Genre 2:</p>
<select name="genre2" class="form-control input-lg">
<?php foreach ($genre as $gen) {
print('<option value='.$gen['idGenre'].'>'.$gen['genre'].'</option>');
} ?>
</select>
</div>
<div class="form-group col-xs-12 col-sm-12 col-md-2">
<p>Genre 3:</p>
<select name="genre3" class="form-control input-lg">
<?php foreach ($genre as $gen) {
print('<option value='.$gen['idGenre'].'>'.$gen['genre'].'</option>');
} ?>
</select>
</div>
</div>
<div class="row">
<div class="form-group col-xs-12 col-sm-12 col-md-2">
<p>Acteur 1:</p>
<input type="text" name="acteurs" id="acteur1" class="form-control input-lg" min="0" max="1000" step="1" value="<?php if(isset($error)){ print($_POST['acteurs']); } ?>" tabindex="1">
</div>
<div class="form-group col-xs-12 col-sm-12 col-md-2">
<p>Acteur 2:</p>
<input type="text" name="acteur2" id="acteur2" class="form-control input-lg" min="0" max="1000" step="1" value="<?php if(isset($error)){ print($_POST['acteurs']); } ?>" tabindex="1">
</div>
<div class="form-group col-xs-12 col-sm-12 col-md-2">
<p>Acteur 3:</p>
<input type="text" name="acteur3" id="acteur3" class="form-control input-lg" min="0" max="1000" step="1" value="<?php if(isset($error)){ print($_POST['acteurs']); } ?>" tabindex="1">
</div>
<div class="form-group col-xs-12 col-sm-12 col-md-2">
<p>Acteur 4:</p>
<input type="text" name="acteur4" id="acteur4" class="form-control input-lg" min="0" max="1000" step="1" value="<?php if(isset($error)){ print($_POST['acteurs']); } ?>" tabindex="1">
</div>
<div class="form-group col-xs-12 col-sm-12 col-md-2">
<p>Acteur 5:</p>
<input type="text" name="acteur5" id="acteur5" class="form-control input-lg" min="0" max="1000" step="1" value="<?php if(isset($error)){ print($_POST['acteurs']); } ?>" tabindex="1">
</div>
<div class="submitVideoToevoegen col-xs-12 col-md-2">
<input type="submit" name="submit" value="Verstuur" class="btn btn-lg " tabindex="5">
</div>
</div>
</div>
</form>
</div>
</div>
该类的代码是：
public function genreToFilm($idFilm, $idGenre){
try{
$stmt = $this->_db->prepare('INSERT INTO FilmGenre
VALUES(:idFilm, :idGenre WHERE idFilm = :idFilm)');
if($stmt->execute(array(':idGenre' => $idGenre,
':idFilm' => $idFilm))){
return true;
} else {
return false;
}
} catch (PDOExeption $e) {
echo '<p class="bg-danger">'.$e->getMessage().'</p>';
}
}
答案 0 :(得分：2)
您在此处缺少列目的地。我不熟悉Pdo方法，但我认为where子句也不在values语句中。
$this->_db->prepare('INSERT INTO FilmGenre VALUES(:idFilm, :idGenre WHERE idFilm = :
你应该这样做：
$this->_db->prepare('INSERT INTO FilmGenre (idFilmColumn, idGenreColumn ) VALUES(:idFilm, :idGenreColumn)') ;