Question

我正在处理FCM消息，我有以下功能：

  public void onMessageReceived(final RemoteMessage remoteMessage)
  {
   final Map<String, String> data = remoteMessage.getData();
   //...
  }

出于测试目的，我有一个包含数据的Json文件 - 我想将我的测试方法中的Json文件发送到onMessagereceived()。因此，我需要使用Json文件初始化RemoteMessage对象，并将此RemoteMessage对象传递给该函数。我该如何初始化？

我的JSON文件：

{
    "data": {
        "id" : "4422",
        "type" : "1",
        "imageUrl" : "https://image.freepik.com/free-vector/android-boot-logo_634639.jpg",
        "smallTitle" : "DoJMA v2",
        "smallSubTitle" : "Update now from Google Play Store",
        "ticker" : "New update for DoJMA",
        "contentInfo" : "",
    "link" : "https://photo2.tinhte.vn/data/avatars/l/1885/1885712.jpg?1402763583",
        "className" : "HomeActivity",
        "page" : "2",
        "bigTitle" : "DoJMA Android app version 2 released!",
        "bigSubTitle" : "Hi folks! New DoJMA update is here! Major redesigning and improvements! This app was made by the Mobile App Club.They work really hard man...and get good products",
        "bigSummaryText" : "Update now"
     },
    "registration_ids": ["dQYmpLUACXQ:APA91bGl-NoIMJ2_DcctF5-OA8ghyWuyrMfsz3uhlj1BySl6axkAsmv5y_7YGfpQQJ2E0lP_fTcxpHpZdkJzY1tbcWA36e78ooxC_b0a1PAank9gFIAUHVZkHKmZT70MPZosCgvRlVfq","dfLXnRI36qY:APA91bFyjLblijVIjGLCGWVeB1B0z5j_3TYqRytJ-8hvuUESpDlX59gWF3hU-I-kA4VrRCPpEVFWl18ZarnPjqxxtZgFkVxoLr77HRex27VN7Mh3xupWykmKq_nnVIlVzrODKwKI7ktM"]
}

Answer 1

您可以使用Postman For Single User进行测试。

发送包含JSON有效内容的通知

网址：https://fcm.googleapis.com/fcm/send

接头：

Authorization: key=<your-api-key>
Content-Type: application/json

正文（点击＆＃39; raw＆＃39;标签）：

{
  "to": "dQYmpLUACXQ:APA91bGl-NoIMJ2_DcctF5-OA8ghyWuyrMfsz3uhlj1BySl6axkAsmv5y_7YGfpQQJ2E0lP_fTcxpHpZdkJzY1tbcWA36e78ooxC_b0a1PAank9gFIAUHVZkHKmZT70MPZosCgvRlVfq",
  "data": {
    "id": "4422",
    "type": "1",
    "imageUrl": "https://image.freepik.com/free-vector/android-boot-logo_634639.jpg",
    "smallTitle": "DoJMA v2",
    "smallSubTitle": "Update now from Google Play Store",
    "ticker": "New update for DoJMA",
    "contentInfo": "",
    "link": "https://photo2.tinhte.vn/data/avatars/l/1885/1885712.jpg?1402763583",
    "className": "HomeActivity",
    "page": "2",
    "bigTitle": "DoJMA Android app version 2 released!",
    "bigSubTitle": "Hi folks! New DoJMA update is here! Major redesigning and improvements! This app was made by the Mobile App Club.They work really hard man...and get good products",
    "bigSummaryText": "Update now"
  }
}

来源：https://firebase.google.com/docs/cloud-messaging/concept-options

Answer 2

TL; DR：初始化RemoteMessage对象不可能。

尝试从您自己的类中初始化RemoteMessage会返回错误：

'RemoteMessage（android.os.Bundle）'在'com.google.firebase.messaging.RemoteMessage'中不公开。无法从外部包裹访问。

我认为你是为了测试而试图这样做的（ stubbing ？）。一般而言（不是说最佳实践，因为我并不完全确定它是最佳实践），建议使用单独的方法接受特定的你需要的价值。参考official example (onMessageReceived)（删除了一些内容）：

@Override
public void onMessageReceived(RemoteMessage remoteMessage) {

    Log.d(TAG, "From: " + remoteMessage.getFrom());

    // Check if message contains a data payload.
    if (remoteMessage.getData().size() > 0) {
        Log.d(TAG, "Message data payload: " + remoteMessage.getData());

        if (/* Check if data needs to be processed by long running job */ true) {
            // For long-running tasks (10 seconds or more) use Firebase Job Dispatcher.
            scheduleJob();
        } else {
            // Handle message within 10 seconds
            handleNow();
        }

    }

    // Check if message contains a notification payload.
    if (remoteMessage.getNotification() != null) {
        Log.d(TAG, "Message Notification Body: " + remoteMessage.getNotification().getBody());
    }

    // Also if you intend on generating your own notifications as a result of a received FCM
    // message, here is where that should be initiated. See sendNotification method below.

}

/**
 * Schedule a job using FirebaseJobDispatcher.
 */
private void scheduleJob() {
    // [START dispatch_job]
    FirebaseJobDispatcher dispatcher = new FirebaseJobDispatcher(new GooglePlayDriver(this));
    Job myJob = dispatcher.newJobBuilder()
            .setService(MyJobService.class)
            .setTag("my-job-tag")
            .build();
    dispatcher.schedule(myJob);
    // [END dispatch_job]
}

/**
 * Handle time allotted to BroadcastReceivers.
 */
private void handleNow() {
    Log.d(TAG, "Short lived task is done.");
}

/**
 * Create and show a simple notification containing the received FCM message.
 *
 * @param messageBody FCM message body received.
 */
private void sendNotification(String messageBody) {
    Intent intent = new Intent(this, MainActivity.class);
    intent.addFlags(Intent.FLAG_ACTIVITY_CLEAR_TOP);
    PendingIntent pendingIntent = PendingIntent.getActivity(this, 0 /* Request code */, intent,
            PendingIntent.FLAG_ONE_SHOT);

    Uri defaultSoundUri= RingtoneManager.getDefaultUri(RingtoneManager.TYPE_NOTIFICATION);
    NotificationCompat.Builder notificationBuilder = new NotificationCompat.Builder(this)
            .setSmallIcon(R.drawable.ic_stat_ic_notification)
            .setContentTitle("FCM Message")
            .setContentText(messageBody)
            .setAutoCancel(true)
            .setSound(defaultSoundUri)
            .setContentIntent(pendingIntent);

    NotificationManager notificationManager =
            (NotificationManager) getSystemService(Context.NOTIFICATION_SERVICE);

    notificationManager.notify(0 /* ID of notification */, notificationBuilder.build());
}

专注于提及的评论：

此外，如果您打算根据收到的FCM消息生成自己的通知，则应在此处启动。请参阅下面的sendNotification方法。

这指出了接受String参数的sendNotification()方法。根据您的情况，您可以简单地传递一个对象，而不是尝试传递已初始化的RemoteMessage（这可能是不可能的，或者至少不是可取的）。方法需要。

有了这个，你几乎测试了处理消息的方法，而不依赖于你最初不是一个类的对象。

_{PS：我的一些解释可能令人困惑，但我希望这是有道理的。}

如何使用Json文件初始化RemoteMessage对象？

2 个答案: