我想找到一种有效的方法:
我有一个字符串:
'1,2,5,11,33'
我想仅将零填充到低于10(有一位数)的数字
所以我想得到
'01,02,05,11,33'
感谢
答案 0 :(得分:18)
您真正关心效率多少?就我个人而言:
string padded = string.Join(",", original.Split(',')
.Select(x => x.PadLeft(2, '0')));
(正如评论中所指出的,如果您使用的是.NET 3.5,则需要在ToArray
之后拨打Select
。
这绝对不是最有效的解决方案,但在我证明它不够高效之前,我会使用它。这是另一种选择......
// Make more general if you want, with parameters for the separator, length etc
public static string PadCommaSeparated(string text)
{
StringBuilder builder = new StringBuilder();
int start = 0;
int nextComma = text.IndexOf(',');
while (nextComma >= 0)
{
int itemLength = nextComma - start;
switch (itemLength)
{
case 0:
builder.Append("00,");
break;
case 1:
builder.Append("0");
goto default;
default:
builder.Append(text, start, itemLength);
builder.Append(",");
break;
}
start = nextComma + 1;
nextComma = text.IndexOf(',', start);
}
// Now deal with the end...
int finalItemLength = text.Length - start;
switch (finalItemLength)
{
case 0:
builder.Append("00");
break;
case 1:
builder.Append("0");
goto default;
default:
builder.Append(text, start, finalItemLength);
break;
}
return builder.ToString();
}
这是可怕的代码,但我认为它会做你想要的......
答案 1 :(得分:5)
string input= "1,2,3,11,33";
string[] split = string.Split(input);
List<string> outputList = new List<string>();
foreach(var s in split)
{
outputList.Add(s.PadLeft(2, '0'));
}
string output = string.Join(outputList.ToArray(), ',');