我有两张桌子:
VM1128:185 [CodeLive] HTTP detected: Connecting using WS
zone.js:630 Unhandled Promise rejection: Template parse errors:
Can't bind to 'options' since it isn't a known property of 'p-dropdown'.
1. If 'p-dropdown' is an Angular component and it has 'options' input, then verify that it is part of this module.
2. If 'p-dropdown' is a Web Component then add 'CUSTOM_ELEMENTS_SCHEMA' to the '@NgModule.schemas' of this component to suppress this message.
3. To allow any property add 'NO_ERRORS_SCHEMA' to the '@NgModule.schemas' of this component. ("<p-dropdown [ERROR ->][options]="cities" [(ngModel)]="selectedCity"></p-dropdown>
"): ng:///AppModule/TestdropdownComponent.html@0:12
'p-dropdown' is not a known element:
1. If 'p-dropdown' is an Angular component, then verify that it is part of this module.
2. If 'p-dropdown' is a Web Component then add 'CUSTOM_ELEMENTS_SCHEMA' to the '@NgModule.schemas' of this component to suppress this message. ("[ERROR ->]<p-dropdown [options]="cities" [(ngModel)]="selectedCity"></p-dropdown>
关系:
T1: Schema(Bucket_Id,B_Id);<br>
T2: Schema(B_Id,V_Id);<br>
我想让所有B_Id OR V_Id对应给定的Bucket_Id。 有人可以帮我这个。
由于
实施例: 表T1
R1: Bucket_Id->B_Id (one to many)<br>
R2: B_Id->V_Id (one to many)<br>
表T2
Bucket_Id B_Id
b1 B1
b1 B2
b2 B3
b2 B4
预期产出
B_Id V_Id
B1 V1
B1 V2
B3 V3
B3 V4
答案 0 :(得分:0)
试试这个
SELECT * FROM T1
UNION ALL
SELECT * FROM T2
答案 1 :(得分:0)
试试这个。
select * from T1
union all
select T1.Bucket_id ,V_Id
from T1 join T2 on T1.B_Id = T2.B_Id