我需要创建一个简单的网页，我可以在其中看到网上过滤器的结果，而不是每天创建过滤器。这样，当我登录arc gis时，结果将每天自动刷新。
我听说有一个API，我的想法是否可行？
答案 0 :(得分：1)
假设您要过滤FeatureLayer - 原始问题不明确，但FeatureLayer似乎合乎逻辑 - 您应该设置definitionExpression属性，如{{3}中所述}。
以下是一个例子：
<!DOCTYPE html>
<html>
<head>
<meta charset="utf-8">
<meta name="viewport" content="initial-scale=1,maximum-scale=1,user-scalable=no">
<title>FeatureLayer - 4.3</title>
<link rel="stylesheet" href="https://js.arcgis.com/4.3/esri/css/main.css">
<script src="https://js.arcgis.com/4.3/"></script>
<style>
html,
body,
#viewDiv {
padding: 0;
margin: 0;
height: 100%;
width: 100%;
}
#filterDiv {
position: absolute;
top: 12px;
right: 12px;
padding: 12px;
background-color: rgba(0, 0, 0, 0.5);
color: white;
}
</style>
<script>
require([
"esri/Map",
"esri/views/MapView",
"esri/layers/FeatureLayer",
"dojo/dom",
"dojo/on",
"dojo/domReady!"
],
function(
Map,
MapView,
FeatureLayer,
dom,
on
) {
var map = new Map({
basemap: "hybrid"
});
var view = new MapView({
container: "viewDiv",
map: map,
extent: {
xmin: -9177811,
ymin: 4247000,
xmax: -9176791,
ymax: 4247784,
spatialReference: 102100
}
});
var featureLayer = new FeatureLayer({
url: "https://services.arcgis.com/V6ZHFr6zdgNZuVG0/arcgis/rest/services/Landscape_Trees/FeatureServer/0",
definitionExpression: "Sci_Name = 'Ulmus pumila'"
});
map.add(featureLayer);
view.then(function() {
on(dom.byId("filterInput"), "change", updateFilter);
function updateFilter(ev) {
featureLayer.definitionExpression = ev.target.checked ?
"Sci_Name = 'Ulmus pumila'" :
undefined;
}
});
});
</script>
</head>
<body>
<div id="viewDiv"></div>
<div id="filterDiv">
<label>Filter
<input id="filterInput" type="checkbox" checked="yes">
</label>
</div>
</body>
</html>