Question

我编写了mysql查询来动态地将行转换为列。当我向prn发送静态值时，此查询正常工作。但是当我从$ prn获取输入时，我将作为空数组出来。以下是代码 -

 $prn=$_GET['prn'];
 echo 'prn:'.$prn;

 $sql = "SET @sql = NULL;
        SELECT
          GROUP_CONCAT(DISTINCT
            CONCAT(
              'GROUP_CONCAT(IF(finding_field = ''',
              finding_field,
              ''',finding_value, NULL)) AS ',
              finding_field
            )
          ) INTO @sql
        FROM cpc_specific_finding;

        SET @sql = CONCAT('SELECT finding_no
                            , ', @sql, ' 
                           FROM cpc_specific_finding 
                           where prn='$prn' 
                           GROUP BY finding_no');

        PREPARE stmt FROM @sql;
        EXECUTE stmt;
        DEALLOCATE PREPARE stmt;";

 $mydata = array();
 if (mysqli_multi_query($localCon,$sql)){
  do{       
    if ($result= mysqli_store_result($localCon)) {

      while ($row=mysqli_fetch_assoc($result)){
         $mydata[] = $row;            
        }         
      mysqli_free_result($result);
      }
    }    
  while (mysqli_next_result($localCon));
 }

 echo json_encode($mydata);

我尝试过编写prn =＆＃39;＆＃34;。$ prn。＆＃34;＆＃39;哪个不起作用。

Answer 1

我得到了答案：D。如果有人发现有帮助，我会发帖回答。

在prn的第三个查询值中传递了''如此删除的引号，它应该是。

export class LanguageActions implements OnInit {

    lang: string;
    private sub: any;

    constructor(private _route: ActivatedRoute) {
    }

    ngOnInit() {
        this.sub = this._route.params.subscribe(params => {
            this.lang= params['lang'];
        });
    }
}

并且有效。

Mysql选择查询，用于在传递静态值工作时传递变量时将行动态转换为列无效

1 个答案: