Question

为了将数据发送到服务器，我使用此解决方案：

https://stackoverflow.com/a/19664927/8033752

但是如何通过POST将数据发送到concret端点RESTful？

Answer 1

这是我的工作方式 - 对PATCH的工作方式类似。下面的代码经过优化，只有有限的注释和异常处理来证明原理。

该示例是一个通用的异步方法，因此它可以接受任何可序列化的内容，包括单个和多个文件流：

/// <summary>
/// Calls a JSON/REST POST service.
/// </summary>
/// <typeparam name="TValue">Type of to be sent value.</typeparam>
/// <param name="loadPackage">Mandatory. The package the post call shall carry.</param>
/// <param name="requestUri">Mandatory. URI which shall be called.</param>
/// <returns>Returns the plain service response.</returns>
public async Task<HttpResponseMessage> CallPostServicePlainAsync<TValue>(
    TValue loadPackage,
    string requestUri)
{
    using (var httpClient = CreateHttpClient()) // or just `new HttpClient()` plus magic
    {
        bool isStream = typeof(TValue) == typeof(Stream);
        bool isMultipleStreams = typeof(TValue) == typeof(Stream[]);
        if (isStream || isMultipleStreams)
        {
            var message = new HttpRequestMessage();
            message.Method = HttpMethod.Post; // that's what makes it a POST :-)
            var content = new MultipartFormDataContent();
            if (isStream) // single stream
                content.Add(new StreamContent(loadPackage as Stream));
            else if (isMultipleStreams) // this is an array of streams
                foreach (Stream stream in loadPackage as Stream[])
                    content.Add(new StreamContent(stream));
            else // oops
                throw new NotImplementedException("incorrect load package.");
            message.Content = content;
            message.RequestUri = new Uri(requestUri);
            return await httpClient.SendAsync(message).ConfigureAwait(false);
        } else {
            // standard serializable content (not streams)
            ...
        }
    }
}

如何将文件发送到端点RESTful C＃？

1 个答案: