Question

我正在使用QT for Windows开发应用程序，我遇到以下问题： 1.一些用户正在打开同一应用程序的多个实例，这是不允许的。如何控制每个用户只打开一次应用程序，而不使用qtsingleapplication？

Answer 1

快速而肮脏的方法是创建一个锁文件。如果锁定文件存在且进程处于活动状态，则新实例将退出。下面给出了一个粗略且未经检查的例子。

bool isProcessRunning( DWORD processID, std::string processName) {

    TCHAR szProcessName[MAX_PATH] = TEXT("<unknown>");

    // Get a handle to the process.

    HANDLE hProcess = OpenProcess( PROCESS_QUERY_INFORMATION | PROCESS_VM_READ, FALSE, processID );

    // Get the process name.

    if ( NULL != hProcess ) {
        HMODULE hMod;
        DWORD cbNeeded;

        if ( EnumProcessModules( hProcess, &hMod, sizeof(hMod), &cbNeeded) )
            GetModuleBaseName( hProcess, hMod, szProcessName, sizeof(szProcessName)/sizeof(TCHAR) );
    }

    // Compare process name with your string
    bool matchFound = !_tcscmp(szProcessName, processName.c_str() );

    // Release the handle to the process.
    CloseHandle( hProcess );

    return matchFound;
};

void lockApp() {
    /*
        *
        * lockApp() -> None
        *
        * Lock app to one instance
        *
        * @return None
        *
    */

    /* Flags */
    int pid = -1;
    bool procRunning = true;

    /* App Lock file: Name and Location */
    QString lockFile = QDir::temp().filePath( "MyAppName.lock" );

    // check for the lock file and see if its stale.
    if ( QFileInfo( lockFile ).exists() ) {

        // OK, lock exists. Now, check if it is stale!
        QFile pidFile( lockFile );
        pidFile.open( QFile::ReadOnly );
        pid = pidFile.readAll().toInt();
        pidFile.close();

        // if /proc/pid doesnot exist, we have a stale lock
        if( isProcessRunning( pid, "MyAppName" ) ) {
            procRunning = false;
            QFile::remove( lockFile );
        }
    }

    else {

        procRunning = false;
    }

    if ( procRunning ) {
        qApp->quit();
        exit( 0 );
    }

    QFile pidFile( lockFile );
    pidFile.open( QFile::WriteOnly );
    pidFile.write( qPrintable( QString::number( qApp->applicationPid() ) ) );
    pidFile.close();
};

第一个功能来自这里。 https://stackoverflow.com/a/13635127/1233513

QT Windows GUI - 如何在没有qtsingleapplication的情况下每次只打开一次实例

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