我有4个不同的数组,每个数组都有不同的长度。我需要弄清楚array.length以了解当前所选数组中的步数。我希望在代码中完成此操作,如果可能,不要在模板中完成。
step.service.ts
public apiURL(){
if (this.heroID == 0){
this.stepsUrl = 'api/stepsLiftSensor';
} else if(this.heroID == 1){
this.stepsUrl = 'api/stepsBucketSensor';
} else if(this.heroID == 2){
this.stepsUrl = 'api/stepsEmptyBucketSensor';
} else if(this.heroID == 3) {
this.stepsUrl = 'api/stepsFullBucketSensor';
}
console.log(this.stepsUrl);
}
getSteps(): Observable<Step[]> {
return this.http.get(this.stepsUrl)
.map(response => response.json().data as Step[]);
}
getStep(id: number): Observable<Step> {
const url = `${this.stepsUrl}/${id}`;
return this.http.get(url)
.map(response => response.json().data as Step);
}
校准detail.component.ts
现在它经历了11个步骤,但是现在数组的大小不同,它会像这样破坏。我希望如此(currentStep&lt; this.stepService.getSteps()。length())但这似乎不起作用,因为它没有长度属性。有没有办法做到这一点?
private currentStep: number = 0; //Variable for the current step
next() {
//Assuming there is another step it pulls the next step up, else it says "End of steps"
if (this.currentStep < 11) { //make sure dont go past number of steps
this.currentStep ++; //Increments the step
this.stepService.getStep(this.currentStep).subscribe(data => (this.mainStepText = data.name)); //Handles return and sets the data it contains to local variable
} else {
this.mainStepText = "Calibration Finished.";
}
}
内存-data.service.ts
import { Injectable } from '@angular/core';
import { InMemoryDbService } from 'angular-in-memory-web-api';
import { Hero } from './hero.class';
import { Step } from './step.class';
import { HeroService } from "./hero.service";
import { StepService } from "./step.service";
import { ActivatedRoute, Params } from "@angular/router";
import 'rxjs/Rx';
@Injectable()
export class InMemoryDataService implements InMemoryDbService {
hero: Hero;
step: Step;
private heroService: HeroService;
private stepService: StepService;
private route: ActivatedRoute;
private location: Location;
constructor() {}
ngOnInit(): void {
this.route.params
.switchMap((params: Params) => this.heroService.getHero(+params['id']))
.subscribe(hero => this.hero = hero);
}
createDb() {
let heroes = [
{id: 1, name: 'Lift Sensor', path: 'stepsLiftSensor'},
{id: 2, name: 'Bucket Sensor', path: 'stepsBucketSensor'},
{id: 3, name: 'Empty Bucket'},
{id: 4, name: 'Full Bucket'}
];
let stepsLiftSensor = [
{id: 1, name: 'test1'},
{id: 2, name: 'test2'},
{id: 3, name: 'test3'},
{id: 4, name: 'test4'},
{id: 5, name: 'test5'}
];
let stepsBucketSensor = [
{id: 1, name: 'test1'},
{id: 2, name: 'test2'},
{id: 3, name: 'test3'},
{id: 4, name: 'test4'},
{id: 5, name: 'test5'}
{id: 6, name: 'test6'},
{id: 7, name: 'test7'},
{id: 8, name: 'test8'},
{id: 9, name: 'test9'},
{id: 10, name: 'test10'}
];
let stepsEmptyBucketSensor = [
{id: 1, name: 'test1'},
{id: 2, name: 'test2'},
{id: 3, name: 'test3'},
{id: 4, name: 'test4'},
{id: 5, name: 'test5'},
{id: 6, name: 'test6'}
];
let stepsFullBucketSensor = [
{id: 1, name: 'test1'},
{id: 2, name: 'test2'},
{id: 3, name: 'test3'},
{id: 4, name: 'test4'},
{id: 5, name: 'test5'}
];
return { heroes, stepsLiftSensor, stepsBucketSensor, stepsEmptyBucketSensor, stepsFullBucketSensor };
}
}
step.class.ts
export class Step {
id: number;
name: string;
}
答案 0 :(得分:2)
重新阅读你的家伙的答案并查看我的代码后,我最终解决了它,我刚刚使用
this.stepService.getSteps().subscribe(data => (this.stepsLength = data.length));
并将其放在我的calibration-detail.component.ts的构造函数中。
答案 1 :(得分:1)
很难遵循你想要的。但是从阅读它之后我可以收集到5次,是你应该在获得步骤后存储长度,并在next()
方法中使用该变量:
stepsLength: number = 0;
getSteps(): Observable<Step[]> {
return this.http.get(this.stepsUrl)
.map(response => response.json().data as Step[])
.do(steps => this.stepsLength = steps.length);
}
答案 2 :(得分:1)
您应该修改服务本身以返回数组的长度以及数据(让我们称之为lengthFromService
)。
您可以将该长度存储在.ts中的变量中(让我们称之为arrLength
)并对该变量进行检查。
所以在你的next()函数中你可以这样做:
this.stepService.getStep(this.currentStep).subscribe(data => {this.mainStepText = data.name; this.arrLength = data.lengthFromService});
如果您需要更多帮助,请发布服务代码或提供data
服务的任何功能代码。