Spring启动 - 自定义登录控制器

Question

我正在尝试将Angular 2与Spring启动集成。登录页面来自Angular 2服务器，我正在尝试使用Spring登录控制器进行身份验证。似乎没有登录控制器，只有servler - j_spring_security_check。如何在不使用Spring Login页面的情况下编写自定义登录控制器。   此外，我的应用程序正在使用Spring boot中的LDAP。

我的控制器如下

@RestController
public class LoginController {

    @Autowired
    private AuthenticationManager authenticationManager;

    @RequestMapping("/api/login")
    public String login(@RequestParam(value="name") String name,@RequestParam(value="password") String password) {
        System.out.println("My login controller");
        System.out.println("User name is " + name);
        System.out.println("Passwird is " + password);
        Authentication request = new UsernamePasswordAuthenticationToken(name, password);

        Authentication result = authenticationManager.authenticate(request);
        System.out.println(result.getPrincipal());
        System.out.println(result.getAuthorities());
        SecurityContextHolder.getContext().setAuthentication(result);
        return "ok";
    }

}



My web security config is as below 

@Configuration
@EnableWebSecurity
public class WebSecurityConfig extends WebSecurityConfigurerAdapter {

    @Override
    protected void configure(HttpSecurity http) throws Exception {
        http
        .authorizeRequests()                                                                             
            //.antMatchers("/api/**").hasRole("MANAGER")
            .antMatchers("/api/login").permitAll()
            .anyRequest().fullyAuthenticated();
            /*.and()
            .formLogin().defaultSuccessUrl("/api");*///.and().exceptionHandling().accessDeniedPage("/404");
    }

    @Override
    public void configure(AuthenticationManagerBuilder auth) throws Exception {
        auth
            .ldapAuthentication()
                .userDnPatterns(new String[]{"uid={0},ou=people"})
                .groupSearchBase("ou=groups")
                .contextSource(contextSource())
                .passwordCompare()
                    //.passwordEncoder(new LdapShaPasswordEncoder())
                    .passwordAttribute("userPassword");
    }

    @Bean
    public DefaultSpringSecurityContextSource contextSource() {
        return  new DefaultSpringSecurityContextSource(Arrays.asList("ldap://localhost:8389/"), "dc=springframework,dc=org");
    }

}