Question

我有一个包含项目的数组，每个项目都有一个duration和一个price。

我想根据duration值过滤掉重复的price值 - 保持最低值。

阵列：

$arr = [
  [
    'duration' => 60, // this item should be filtered
    'price' => 100
  ],
  [
    'duration' => 120,
    'price' => 190
  ],
  [
    'duration' => 60, // this one should remain in array
    'price' => 75
  ]
]

我使用Laravel作为框架，因此我可以使用集合方法。

所以我现在实现如下：

$arr->sortByDesc('price')
  ->keyBy('duration') // duplicate entries are overwritten 
                      // with the latest/lowest value
  ->sortBy('price');

但这感觉有点粗略......

Answer 1

这样可以解决问题：

$arr = [
  [
    'duration' => 60, // this item should be filtered
    'price' => 100
  ],
  [
    'duration' => 120,
    'price' => 190
  ],
  [
    'duration' => 60, // this one should remain in array
    'price' => 75
  ]
];

rsort($arr);   // sort the subarrays by duration DESC
// assign keys to each subarray using duration value
$arr=array_values(array_combine(array_column($arr,'duration'),$arr));
// this overwrites more expensive subarrays with less expensive subarrays
var_export($arr);

输出：

array (
  0 => 
  array (
    'duration' => 120,
    'price' => 190,
  ),
  1 => 
  array (
    'duration' => 60,
    'price' => 75,
  ),
)

Answer 2

怎么样？

$collection = collect($arr);
$filtered = $collection->sortBy('duration')->sortBy('price')->unique('duration');

它也可以作为

$collection = collect($arr);
$filtered = $collection->sortBy('price')->unique('duration');

根据同一数组

2 个答案: