Question

您好我正在尝试加入User和Candidate表。我想要来自firstname表的列lastname，email，phone，Candidate，并加入password表的User列。我试过这样做，但得到了一些错误。我的代码如下：

CREATE TABLE `candidate` (`candidate_id` bigint(12) NOT NULL,`user_id` int(11) DEFAULT NULL,`firstname` varchar(50) COLLATE utf8_unicode_ci DEFAULT NULL,`lastname` varchar(50) COLLATE utf8_unicode_ci DEFAULT NULL,`dob` date DEFAULT NULL,`gender` varchar(45) COLLATE utf8_unicode_ci DEFAULT NULL,`email` varchar(100) COLLATE utf8_unicode_ci NOT NULL,`phone` varchar(45) COLLATE utf8_unicode_ci DEFAULT NULL,`address_id` int(11) DEFAULT NULL,`profile_title` varchar(120) COLLATE utf8_unicode_ci DEFAULT NULL,`profile_summary` varchar(10000) COLLATE utf8_unicode_ci DEFAULT NULL,`total_experience` int(11) DEFAULT NULL COMMENT 'year,month',`current_location` varchar(45) COLLATE utf8_unicode_ci DEFAULT NULL,`current_salary` double DEFAULT NULL,`expected_salary` double DEFAULT NULL,`status` varchar(45) COLLATE utf8_unicode_ci DEFAULT NULL,`percentage` int(45) DEFAULT NULL,`updated_on` timestamp NULL DEFAULT CURRENT_TIMESTAMP,`noticeperiod` int(11) DEFAULT NULL,`martialstatus` varchar(45) COLLATE utf8_unicode_ci DEFAULT NULL,`currentoffer` double DEFAULT NULL,`idproof` varchar(45) COLLATE utf8_unicode_ci DEFAULT NULL,`industry` varchar(200) COLLATE utf8_unicode_ci DEFAULT NULL,`functionalarea` varchar(200) COLLATE utf8_unicode_ci DEFAULT NULL,`functionalrole` varchar(200) COLLATE utf8_unicode_ci DEFAULT NULL,`resign` bit(1) DEFAULT NULL,`preferlocation` varchar(1000) COLLATE utf8_unicode_ci DEFAULT NULL,`type` varchar(45) COLLATE utf8_unicode_ci DEFAULT NULL,`notice_period_update` timestamp NULL DEFAULT NULL,`passport` bit(1) DEFAULT NULL,`gross_salary` double DEFAULT NULL,`profile_type` varchar(12) COLLATE utf8_unicode_ci DEFAULT NULL,`rrm_user_id` int(11) DEFAULT NULL, PRIMARY KEY (`candidate_id`), KEY `Candidate_Address_idx` (`address_id`),KEY `Can_user` (`user_id`),KEY `CandidateStatus_idx` (`status`),KEY `CandidatePercent_idx` (`percentage`), KEY `user_id_idx` (`rrm_user_id`),CONSTRAINT `Can_user` FOREIGN KEY (`user_id`) REFERENCES `user` (`id`) ON DELETE CASCADE ON UPDATE CASCADE,CONSTRAINT `Candidate_Address` FOREIGN KEY (`address_id`) REFERENCES `address`(`id`) ON DELETE CASCADE ON UPDATE CASCADE, CONSTRAINT `user_id` FOREIGN KEY (`rrm_user_id`) REFERENCES `user` (`id`) ON DELETE NO ACTION ON UPDATE NO ACTION) ENGINE=InnoDB DEFAULT CHARSET=utf8 COLLATE=utf8_unicode_ci;

我的用户表：

CREATE TABLE `user` (`id` int(11) NOT NULL AUTO_INCREMENT,`username` varchar(255) COLLATE utf8_unicode_ci NOT NULL,`password` varchar(50) COLLATE utf8_unicode_ci DEFAULT NULL,`first_name` varchar(100) COLLATE utf8_unicode_ci DEFAULT NULL,`last_name` varchar(100) COLLATE utf8_unicode_ci DEFAULT NULL,`type` varchar(50) COLLATE utf8_unicode_ci DEFAULT NULL,`active` bit(1) DEFAULT NULL,`deleted` bit(1) DEFAULT NULL,`timezone` varchar(50) COLLATE utf8_unicode_ci DEFAULT NULL,`created_on` timestamp NULL DEFAULT NULL,`updated_on` timestamp NULL DEFAULT CURRENT_TIMESTAMP,`activationcode` varchar(50) COLLATE utf8_unicode_ci DEFAULT NULL,`secure_key` varchar(16) COLLATE utf8_unicode_ci DEFAULT NULL,PRIMARY KEY (`id`),UNIQUE KEY `username_UNIQUE` (`username`)) ENGINE=InnoDB AUTO_INCREMENT=1505 DEFAULT CHARSET=utf8 COLLATE=utf8_unicode_ci;

我的实体类：

@Table(name = "CANDIDATE")public class SignUp {
@Id
@GeneratedValue(strategy = GenerationType.IDENTITY)
private String candidate_id;
@Column
private String firstname;
@Column
private String lastname;
@Column
private String email;
@Column
private String phone;

public String getCandidate_id() {
    return candidate_id;
}

public void setCandidate_id(String candidate_id) {
    this.candidate_id = candidate_id;
}

public String getFirstname() {
    return firstname;
}

public void setFirstname(String firstname) {
    this.firstname = firstname;
}

public String getLastname() {
    return lastname;
}

public void setLastname(String lastname) {
    this.lastname = lastname;
}

public String getEmail() {
    return email;
}

public void setEmail(String email) {
    this.email = email;
}

public String getPhone() {
    return phone;
}

public void setPhone(String phone) {
    this.phone = phone;
}
@OneToOne(cascade = CascadeType.ALL)
@JoinColumn(name = "candidate_id")
private Password password;

public Password getPassword() {
    return password;
}

public void setPassword(Password password) {
    this.password = password;
}

对于用户表：

@Table(name = "USER")public class Password { @Id
@GeneratedValue(strategy = GenerationType.IDENTITY)
private String id;
@Column
private String password;

public String getId() {
    return id;
}

public void setId(String id) {
    this.id = id;
}

public String getPassword() {
    return password;
}

public void setPassword(String password) {
    this.password = password;
}

@OneToOne(cascade = CascadeType.ALL)
@JoinColumn(name = "user_id")
private SignUp signUp;

public SignUp getSignUp() {
    return signUp;
}

public void setSignUp(SignUp signUp) {
    this.signUp = signUp;
}

获得的错误是：

Hibernate: 
select
    password0_.id as id1_1_0_,
    password0_.password as password2_1_0_,
    password0_.user_id as user_id4_1_0_,
    signup1_.candidate_id as candidat1_0_1_,
    signup1_.email as email2_0_1_,
    signup1_.firstname as firstnam3_0_1_,
    signup1_.lastname as lastname4_0_1_,
    signup1_.phone as phone5_0_1_ 
from
    User password0_ 
left outer join
    CANDIDATE signup1_ 
        on password0_.user_id=signup1_.candidate_id 
where
    password0_.id=?

2017年6月1日下午4:48:45 org.hibernate.engine.jdbc.spi.SqlExceptionHelper logExceptions WARN： SQL错误：1054，SQLState：42S22 Jun 01,2017 4:48:45 PM org.hibernate.engine.jdbc.spi.SqlExceptionHelper logExceptions错误：未知列＆＃39; password0_.user_id＆＃39;在＆＃39;字段列表＆＃39;

Answer 1

您的映射很好，您只是错过了基于此映射的user_id语句中的CREATE TABLE user：

@OneToOne(cascade = CascadeType.ALL)
@JoinColumn(name = "user_id")
private SignUp signUp;

hibernate期望通过该列连接到CERTIFICATE表。

另外不要忘记在DDL中添加外键语句。

Answer 2

尝试使用Jboss逆向工程工具进行hibernate生成域并避免此类错误。这非常简单，您可以在5分钟内从数据库表创建域。

错误在hibernate中加入表

2 个答案: