Question

这是我使用的this答案：

SET @pattern = '%_movielist';

SELECT concat('TRUNCATE TABLE ', GROUP_CONCAT(concat(TABLE_NAME)), ';')
INTO @truncatelike FROM INFORMATION_SCHEMA.TABLES
WHERE TABLE_NAME LIKE @pattern;

SELECT @truncatelike;

PREPARE stmt FROM @truncatelike;
EXECUTE stmt;
DEALLOCATE PREPARE stmt;

但我收到此错误Access denied for user 'root'@'%' to database 'information_schema'。我究竟做错了什么？它似乎适用于其他用户

Answer 1

您尝试在＆＃34; information_schema＆＃34; 数据库上执行此语句。阅读有关此数据库[https://dev.mysql.com/doc/refman/5.7/en/information-schema.html]

的更多信息

您不应该在information_schema数据库上运行语句（除非您真的知道自己在做什么）。该数据库充当了一个＆＃34; meta＆＃34;指示服务器如何运行的存储库。有可能你没有必要触摸它，如果你这样做，你很可能会破坏你的服务器。

这已在这里得到解答。 [#1044 - Access denied for user 'root'@'localhost' to database 'information_schema'

对上面的限制：只有当语句返回的表的数量超过1个表时，此查询才有效，您需要在迭代中使用它。

为了使所有匹配模式的表能够使用存储过程。

请更改程序名称

CREATE PROCEDURE `new_procedure`()
BEGIN
-- Pattern to Match 
SET @pattern = '%_movielist';
-- Temporary Table to Store the Result of The Select Statement

CREATE TEMPORARY TABLE IF NOT EXISTS Table_ToBeTruncated 
    (
       Id int NOT NULL AUTO_INCREMENT,TableName varchar(100),
       PRIMARY KEY (id)
    );

-- Insert all the TableName  to be Truncated 
    insert Table_ToBeTruncated(TableName)
    SELECT distinct concat('TRUNCATE TABLE `', TABLE_NAME, '`;')
    FROM INFORMATION_SCHEMA.TABLES
    WHERE TABLE_NAME LIKE @pattern and TABLE_SCHEMA = 'movielist';

-- Declare a variable to count the no of records to be truncated.
SET @count=(Select count(*)from Table_ToBeTruncated);

-- Iterate the list 
WHILE @count> 0 DO

    -- Pick One table from the Temporary Table List;
    SELECT TableName into @truncatelike from Table_ToBeTruncated where ID= @count;

    -- Prepare the statement
    PREPARE stmt FROM @truncatelike;
    EXECUTE stmt;
    DEALLOCATE PREPARE stmt;

    -- Decrease the counter.
    set @count = @count- 1;

END WHILE;

drop TEMPORARY TABLE IF EXISTS Table_ToBeTruncated ;

END

TRUNCATE匹配名称模式的所有表

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